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3 years ago

6

find the rate of positive acceleration of an automobile which went from a complete stop to a velocity of 30 meters per second in

10 seconds

1 answer:

maks197457 [2]3 years ago

3 0

Answer:

3 m/s^2

Explanation:

acceleration= Change in velocity/time

= 30-0 / 10

= 30/10

=3 m/s^2

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Three resistors of resistances, R1=10Ω, R2=5Ω, R3=20Ω are connected in a circuit in such way that same amount of current flows t

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Answer

Explanation:

As the three resistors are connected in series, the expression to be used for the

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RT = R1 + R2 + R3

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5 10 15 RT + R1 + R2 + R3 + +

We perform the mathematical operations that lead us to the result we are looking for:

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3 years ago

Light of wavelength 575 nm passes through a double-slit and the third order bright fringe is seen at an angle of 6.5^degree away

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Answer:

The correct option is C

Explanation:

From the question we are told that

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The angle is $\theta = 6.5^o$

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Generally for constructive interference

$dsin \theta = n * \lambda$

=> $d = \frac{n * \lambda }{ sin \theta }$

=> $d = \frac{3 * 575 *10^{-9} }{ sin 6.5 }$

=> $d = 15.24 *10^{-6} \ m$

=> $d = 15 \mu m$

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4 years ago

You can increase the capacitance of a capacitor by A. Decreasing the plate spacing B. Increasing the plate spacing. ° C. Decreas

eimsori [14]

You can increase the capacitance of a capacitor by decreasing the plate spacing (A) or by increasing the area of the plates (D).

'A' and 'D' both do the job, so the correct choice is<em> (E)</em> .

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3 years ago

The more force you put on a material, the more it .......?

Brilliant_brown [7]

Answer:

the faster it moves(if it is free) . the less the inertia (potential) and the more the inertia (kinetic)

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3 years ago

Read 2 more answers

a ball is dropped from rest at a height of 45.0 m above the ground. ignore the effects of air resistance. What is the speed of c

NemiM [27]

So, the final velocity of the ball when it is 10.0 m above the ground approximately <u>26.2 m/s</u>.

<h3>Introduction</h3>

Hi ! In this question, I will help you. This question uses the principle of final velocity in free fall. Free fall occurs only when an object is dropped (without initial velocity), so the falling object is only affected by the presence of gravity. In general, the final velocity in free fall can be expressed by this equation :

$\boxed{\sf{\bold{v = \sqrt{2 \times g \times h}}}}$

With the following condition :

v = final velocity (m/s)
h = height or any other displacement at vertical line (m)
g = acceleration of the gravity (m/s²)

<h3>Problem Solving</h3>

We know that :

$\sf{h_1}$ = initial height = 45.0 m
$\sf{h_2}$ = final height = 10.0 m
g = acceleration of the gravity = 9.8 m/s²

Note :

At this point 10 m above the ground, the object can still complete its movement up to exactly 0 m above the ground.

What was asked :

v = final velocity = ... m/s

Step by Step

$\sf{v = \sqrt{2 \times g \times \Delta h}}$

$\sf{v = \sqrt{2 \times g \times (h_1 - h_2)}}$

$\sf{v = \sqrt{2 \times 9.8 \times (45 - 10)}}$

$\sf{v = \sqrt{19.6 \times 35}}$

$\sf{v = \sqrt{686}}$

$\boxed{\sf{v \approx 26.2 \: m/s}}$

<h3>Conclusion</h3>

So, the final velocity of the ball when it is 10.0 m above the ground approximately 26.2 m/s.

<h3>See More :</h3>

The relationship between acceleration and the change in velocity and time in free fall brainly.com/question/26486625

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2 years ago