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3 years ago

The time for a sound wave to travel between two people is 0.80 s,

Physics

1 answer:

sasho [114]3 years ago

4 0

Answer:

Explanation:

Using the below formula

Speed of sound = ( distance between observers) *2/(total time taken)

Now putt the given values ,

time taken = 0.80 sec

distance = 256 m

hence

V of sound= 256*2/0.80

V of sound = 640 m/sec

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erma4kov [3.2K]

<h2>Explanation:</h2><h3>3. </h3>

When light bounces back, it is <em>reflected</em>. (That's why you see your <em>reflection</em> in a mirror.) When light is bent from the path it is taking, it is <em>refracted</em>. The only answer choice that makes correct use of these terms is the third choice:

Part of the ray is <em>refracted</em> into ray B; part of the ray is <em>reflected</em> as ray R.

_____

The index of refraction is the ratio of the sine of the angle of incidence to the sine of the angle of refraction. Both angles are measured from the normal to the surface. The angle of refraction here is 12.5° less than the angle of incidence, 44°, so is 31.5°. Then the index of refraction of the medium is ...

n = sin(44°)/sin(31.5°) = 0.69466/0.52250 = 1.3299 ≈ 1.33

none of the offered choices is correct. The closest is 1.34.

8 0

3 years ago

If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the cu

zubka84 [21]

Answer:

minimum speed is 15.35 m/s

frictional coefficient is 0.26

Explanation:

given data

radius = 84 m

angle = 16°

speed = 16 km/h = 4.43 m/s

to find out

minimum speed and minimum coefficient

solution

we will apply here formula for velocity that is

velocity² = radius × g × tanθ

v² = 84 × 9.8 × tan16

v² = 236.04

v = 15.35 m/s

and

we find first friction force here

friction force 1 = m v² /r

friction force 1 = m (15.35)² / 84 = 2.80 m

and

friction force 2 = m v² /r

friction force 2 = m (4.43)² / 84 = 0.245 m

so total friction force = f1 - f2

total friction force = 2.80 - 0.245 = 2.55 m

so frictional coefficient = friction force /g

frictional coefficient = 2.55 / 9.8

so frictional coefficient is 0.26

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