Answer:
s = 2.65 m
Explanation:
given,
mass of block,M = 1.3 Kg
mass of bullet,m = 50 g = 0.05 Kg
speed of bullet,u = 250 m/s
speed of bullet after collision,v = 100 m/s
distance traveled by the block = ?
Assuming the angle of inclination of ramp equal to 40°
calculating the speed of the block
using conservation of momentum
M u' + m u = m v + M v'
initial speed of the block is equal to zero
0 + 0.05 Kg x 250 = 0.05 x 100 + 1.3 x v'
1.3 v' = 7.5
v' = 5.77 m/s
now, calculation of acceleration
equation the horizontal component
-mg sin θ = ma
a = - g sin θ
a = - 9.8 x sin 40°
a = -6.29 m/s²
using equation of motion for the calculation of distance moved by the block
v² = u² + 2 a s
0² = 5.77² + 2 x (-6.29) x s
12.58 s = 33.29
s = 2.65 m
hence, the distance moved by the block is equal to 2.65 m
Radio waves, Television waves, Microwaves, Infrared light, Visible light, Ultraviolet rays, X - rays, Gamma rays, and i think thats about it.
Sorry if i get this wrong Im in elementry school
Hope this helped :)
Answer:
The frequency does not depend on the amplitude for any (ideal) mechanical or electromagnetic waves.
In electromagnetism we have that the relation is:
Velocity = wavelenght*frequency.
So the amplitude of the wave does not have any effect here.
For a mechanical system like an harmonic oscillator (that can be used to describe almost any oscillating system), we have that the frequency is:
f = (1/2*pi)*√(k/m)
Where m is the mass and k is the constant of the spring, again, you can see that the frequency only depends on the physical properties of the system, and no in how much you displace it from the equilibrium position.
This happens because as more you displace the mass from the equilibrium position, more will be the force acting on the mass, so while the "path" that the mass has to travel is bigger, the mas moves faster, so the frequency remains unaffected.
Answer:
Explanation:
Given:
- mass of skier,
- initial velocity of skier,
- height of the hill,
- spring constant,
<u>final velocity of skier before coming in contact of spring:</u>
Using eq. of motion:
<u>Now the time taken by the skier to reach down:</u>
<u>Now we calculate force using Newton's second law:</u>
<u>∴Compression in spring before the skier momentarily comes to rest:</u>
Answer:
“I had to cut off the third prong on the electrical plug so that it would fit in the extension cord.”
Explanation:
A good method to find the customer at greater risk of receiving an electric shock is to discard the options.
If we analyze the fourth option "I always make sure that I am standing in a dry area before operating electrical equipment.", we will see that the customer minimizes the risk of electric conduction through a fluid. This precaution also minimizes the risk of electric shock.
The third option "I always read the owner’s manual when I purchase a new electrical appliance." It tells us that the customer knows how to properly use the electrical equipment that manipulates and knows the do and do not of such devices, so the risk of electric shock is reduced.
In the second option, "My bread got stuck in my toaster this morning, and I unplugged it before trying to remove it." The customer made sure to interrupt the electric flow to the device before proceeding and try to remove the jammed bread. If there is no electric current, there will be no electric shock to the customer.
The first option "I had to cut off the third prong on the electrical plug so that it would fit in the extension cord." It tells us that the client altered the cord extension in an inappropriate manner, since the equipment is not designed to work with two prongs. Because the design conditions are not being met, it is possible that the equipment malfunctions and this malfunction could result in the customer receiving an electric shock.
I hope the explanation was clear for you. If you have any further question, I'll be happy to assist you. :D
