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lutik1710 [3]
3 years ago
10

5x-3x(26x-7x-28x) systems of equation

Mathematics
1 answer:
labwork [276]3 years ago
3 0

Simplifying
5x + 2(8x + -9) = 3(x + 4) + -5(2x + 7)

Reorder the terms:
5x + 2(-9 + 8x) = 3(x + 4) + -5(2x + 7)
5x + (-9 * 2 + 8x * 2) = 3(x + 4) + -5(2x + 7)
5x + (-18 + 16x) = 3(x + 4) + -5(2x + 7)

Reorder the terms:
-18 + 5x + 16x = 3(x + 4) + -5(2x + 7)

Combine like terms: 5x + 16x = 21x
-18 + 21x = 3(x + 4) + -5(2x + 7)

Reorder the terms:
-18 + 21x = 3(4 + x) + -5(2x + 7)
-18 + 21x = (4 * 3 + x * 3) + -5(2x + 7)
-18 + 21x = (12 + 3x) + -5(2x + 7)

Reorder the terms:
-18 + 21x = 12 + 3x + -5(7 + 2x)
-18 + 21x = 12 + 3x + (7 * -5 + 2x * -5)
-18 + 21x = 12 + 3x + (-35 + -10x)

Reorder the terms:
-18 + 21x = 12 + -35 + 3x + -10x

Combine like terms: 12 + -35 = -23
-18 + 21x = -23 + 3x + -10x

Combine like terms: 3x + -10x = -7x
-18 + 21x = -23 + -7x

Solving
-18 + 21x = -23 + -7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7x' to each side of the equation.
-18 + 21x + 7x = -23 + -7x + 7x

Combine like terms: 21x + 7x = 28x
-18 + 28x = -23 + -7x + 7x

Combine like terms: -7x + 7x = 0
-18 + 28x = -23 + 0
-18 + 28x = -23

Add '18' to each side of the equation.
-18 + 18 + 28x = -23 + 18

Combine like terms: -18 + 18 = 0
0 + 28x = -23 + 18
28x = -23 + 18

Combine like terms: -23 + 18 = -5
28x = -5

Divide each side by '28'.
x = -0.1785714286

Simplifying
x = -0.1785714286
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The first term is 612.

The common ratio is 1.08 and

The recursive rule is a_{n} = a^{n-1} \times r

<u>Step-by-step explanation:</u>

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

<u>The first term :</u>

In geometric sequence, the first term is given as a_{1}.

⇒ a_{1} = 612

Now, the geometric sequence follows as 612, 661, ........

<u>The common ratio (r) :</u>

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

<u>To find the recursive rule :</u>

A geometric series is of the form  a,ar,ar2,ar3,ar4,ar5........

Here, first term a_{1} = a and other terms are obtained by multiplying by r.

  • Observe that each term is r times the previous term.
  • Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form a_{n} = a^{n-1} \times r

This is called recursive formula for geometric sequence.

We know that r = 1.08 and a_{1} = 612.

To find the second term a_{2}, use the recursive rule a_{n} = a^{n-1} \times r

⇒ a_{2} = a^{2-1}\times r

⇒ a_{2} = a^{1}\times r

⇒ a_{2} = 612\times 1.08

⇒ a_{2} = 661

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