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san4es73 [151]
2 years ago
13

Please answer as soon as possible PLEASE

Mathematics
1 answer:
tatuchka [14]2 years ago
7 0

Answer:

x>-5

Step-by-step explanation:

-5(x+7)<-10

divide by -5 (and because we divided by a negative number swap the inequality sign)

x+7>2

x> -5

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The graph of which function(s) will contain the point (4, 12)? y = x + 8 y = 3x y = 2x y = x + 6
Alex777 [14]

Answer:

y=x+8  and y=3x

Step-by-step explanation:

The Given point is (4,12)

now we can substitute the point in each of the function and check wether it lies on it or not.

A.  y=x+8

substitute y=12,x=4

12=4+8=12 which is true

B.  y=3x

substitute y=12,x=4

12=3*4=12 which is true

C.  y=2x

substitute y=12,x=4

12=2*4=8  which is not true

D.  y=x+6

substitute y=12,x=4

12=4+6=10 . which is not true

Therefore option A and B are correct.

4 0
3 years ago
Find the thirtieth term of the following sequence.
Nikolay [14]
You are adding 2 each time.

You are trying to find the 30th term, in which 4 are shown. 

Subtract 4 from 30

30 - 4 = 26

Multiply 26 with 2

26 x 2 = 52

Add 52 to the last number given (0)

0 + 52 = 52

52 is your answer

hope this helps
4 0
3 years ago
Given circle U with diameter ST and radius UQ. QR is tangent to U at Q. If
vfiekz [6]

Answer:

QT = 18

Step-by-step explanation:

4 0
2 years ago
Find the equation of a straight line passing through the point (0,1) which is perpendicular to the line y=-2x+2
alexandr1967 [171]

Answer:

y = \frac{1}{2} x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x + 2 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-2} = \frac{1}{2}

The line crosses the y- axis at (0, 1) ⇒ c = 1 , then

y = \frac{1}{2} x + 1 ← equation of perpendicular line

3 0
2 years ago
If <br>4x+(y+x)=180<br>what is x? what is y?​
uysha [10]

Step-by-step explanation:

4x+(y+x)=180\\\\\text{Solve for}\ x:\\\\4x+y+x=180\qquad\text{combine like terms}\\\\(4x+x)+y=180\qquad\text{subtract}\ y\ \text{from both sides}\\\\5x=180-y\qquad\text{divide both sides by 5}\\\\\dfrac{5x}{5}=\dfrac{180-y}{5}\\\\\boxed{x=\dfrac{180-y}{5}}\\\\\text{Solve for}\ y:\\\\5x+y=180\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\\boxed{y=180-5x}

7 0
3 years ago
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