It is the 'backstage' in which you can <span>save, select a template, change document properties, and close or exit excel</span>
Answer:
import java.util.Scanner;
public class ss11{
public static void main (String[]args) {
Scanner keyboard = new Scanner (System.in)
String a1, a2, a3, a4, a5;
int i1, i2, i3, i4, i5;
System.out.println("Enter a four bit binary number:");
a1= keyboard.next();
a2= a1.substring(0,1);
a3= a1.substring(1,2);
a4= a1.substring(2,3);
a5= a1.substring(3,4);
i1 = Integer.parseInt(a2);
i2 = Integer.parseInt(a3);
i3 = Integer.parseInt(a4);
i4 = Integer.parseInt(a5);
i1= i1 * 8;
i2= i1 * 4;
i3= i1 * 2;
i4= i1 * 1;
i5= i1+i2+i3+i4;
System.out.println("The converted decimal number is: +i5);
}
}
Explanation:
Answer:
public static String repeat(String text, int repeatCount) {
if(repeatCount < 0) {
throw new IllegalArgumentException("repeat count should be either 0 or a positive value");
}
if(repeatCount == 0) {
return "";
} else {
return text + repeat(text, repeatCount-1);
}
}
Explanation:
Here repeatCount is an int value.
at first we will check if repeatCount is non negative number and if it is code will throw exception.
If the value is 0 then we will return ""
If the value is >0 then recursive function is called again untill the repeatCount value is 0.
60,436 is larger.
A byte is a sequence of 8 bits (enough to represent one alphanumeric character) processed as a single unit of information. A single letter or character would use one byte of memory (8 bits), two characters would use two bytes (16 bits).
