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3 years ago

Which of the following correctly describes a production isoquant?

Business

1 answer:

evablogger [386]3 years ago

4 0

Answer:

An isoquant is a curve that shows the least-cost combinations of inputs that can produce a given level of output.

Explanation:

Isoquants are lines of equal values that are meant to show a set of points that have the same quantity of output when changing the quantities of more than two inputs.

It also shows an extent to which the firm has the ability to substitute two or different products to attain the same level of the outputs.

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Bonds are a far more important source of financing than are stocks B. Financial intermediaries such as banks are the least impor

Anna71 [15]

Answer:

Bonds are a far more important source of financing than are stocks

Explanation:

There is so much of risk associated with the issue of stock. Though it is essential for any business to issue some stock, but bonds are always favorable as they have a defined maturity, defined amount associated, and defined interest payment.

There is no direct payment of interest in bonds but the expense is to be recorded in books as per the matching and accrual principle.

The discounted value of interest to be paid on maturity is recorded.

Further, there is a tax benefit on bond payments.

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3 years ago

Suppose that a substantial number of discouraged workers become encouraged about potential job prospects and start looking for w

zzz [600]

Hello, the answer is Decrease

6 0

3 years ago

Automobile repair costs continue to rise with the average cost now at $367 per repair.† Assume that the cost for an automobile r

vovikov84 [41]

Answer:

a) 0.1728

b) 0.09183

c) 0.7354

d) $ 222.25

Explanation:

Given

mean = $\mu$ = $367

Standard deviation = $\sigma$ =$88

Cost of automobile repair is normally distributed.

a) We have to find P( x > 450 )

P( x > 450 ) = 1 - P( x <= 450 )

Using excel function, P( x <= x ) = NORMDIST (x, $\mu$ , $\sigma$ , 1 )

P( x > 450 ) = 1 - NORMDIST( 450 , 367, 88, 1 )

= 1 - 0.8272 = 0.1728

P( x > 450 ) = 0.1728

b) P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( x < 250 ) = 0.09183

c) P( 250 < x < 450 ) = P( x <450 ) - P( x < 250 )

P( x <450 ) = NORMDIST( 450 , 367, 88, 1 ) = 0.8272

P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( 250 < x < 450 ) = 0.8272 - 0.09183 = 0.7354

P( 250 < x < 450 ) = 0.7354

d) We have P( X < a ) = 0.05

We have to find a.

Using Excel, = NORMINV ( Probability, $\mu$ , $\sigma$ )

a = NORMINV ( 0.05 , 367, 88 ) = 222.2529

Cost = $ 222.25

8 0

3 years ago

Granite State Airlines serves the route between New York and Portsmouth, NH, with a single-flight-daily 100-seat aircraft. The o

TEA [102]

Answer:

Given data: One flight with total seats = 100

Full fare passengers, cost per ticket=$150, mean=56 passengers, SD=23

Discount fare passengers, cost per ticket=$100, mean=88 passengers, SD=44

(a) Here, though there is a hint to use the CDF, since the confidence interval is not given we will make some simplying assumptions that will reduce the complexity of the question, of course keeping the question statistically correct.

this question wants us to maximize total revenue per flight (one way), we can do that by taking only full fare passengers or total revenue will be 150*100=$15,000, but since historical probability shows a mean of 56 with a standard deviation of 23, we can assume in best case scenario total full fare ticket passengers will be 56+23=79, leaving 21 tickets for discount passenger, in this case the total revenues will be 79*150+21*100=$13,950

(b) Now, the new constrained policy is giving a clear cut number of seats to each category of pasengers, 44 for discount (total revenues 44*100) and 56 for full fare (total revenues 56*150) both of which are within the probabilities given earlier (full fare mean=56, discount mean=88). Total revenues in case will be 44*100+56*150=$12,800.

(c) Gain is the difference of the excess revenues in both cases of optimal total revenues and limited seats policy or answer (a) - answer (b) = $13,950- $12,800=$1,150

(d) Realistically speaking, there is no answer for this question without a clear cut confidence interval. Another simplifying assumption we can make here is taking the mean passengers as expected bookings (can be tweaked once confidence interval or degree of significance is given). so total revenues in this case will be 44*100 from discount and 56*150 from full fare passengers. That is still similar to answer (c) due to our assumption/lack of constraints, so our optimal booking will be 54 full fare tickets and 44 discount passenger tickets. You can also take worst case scenario by subtracting SD of each passenger type from the mean or go the best case scenario in which SD of full fare will be added to the mean while the pending seats (left over from 100) will be the total to discount fare for optimal revenue collection.

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3 years ago

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Who is Justin Bieber

Stella [2.4K]

Answer:

He a celebrity. One of his biggest songs are Baby, Love yourself, what do you mean, sorry .

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3 years ago

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