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mr Goodwill [35]
3 years ago
9

Plz help! It is a Grade! I will do brainsiest

Mathematics
1 answer:
ikadub [295]3 years ago
3 0

Answer: I can only see the big boxes so will answer them

5/6 - 1/3

Multiply the two denominators together get 18

Then multiply the bottom denominator with the opposite numerator

The sum has now changed to:

15/18 - 6/18

15 - 6 = 9

9/18 can then be simplified to 1/2

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OMG HELP PLS IM PANICKING OMG OMG I GOT A F IN MATH AND I ONLY HAVE 1 DAY TO CHANGE MY GRADE BECAUSE TOMORROW IS THE FINAL REPOR
Ahat [919]

Answer:

2/5 bucket

Step-by-step explanation:

1/2 and 3/4 are equal. So 2/5 is wrong.

hope this helped, and please mark as Brainliest <3

7 0
3 years ago
Okkkkkkkkkkkkkkkkkkkkkkkk
kirza4 [7]
2x+3y=17 --- 1
3x+6y=30 --- 2
x+2y=10
x=10-2y --- 3
Sub 3 into 1,
2(10-2y)+3y=17
20-4y+3y-17=0
3-y=0
y=3 --- 4
Sub 4 into 3,
x=10-2(3)
x=4

Therefore, Answer is (4,3).
4 0
3 years ago
Read 2 more answers
Four less than the product of <br> 8<br> and a number equals <br> 7
erica [24]
8n-4=7.................................................
8 0
3 years ago
The rectangle below has an area of x^2+8x+15x
Darina [25.2K]

Answer:

The length of the rectangle is x+5.

Step-by-step explanation:

Given : The rectangle below has an area of x^2+8x+15 square meter and a width of  x+3 meter.

To find : What expression represents the length of the rectangle?

Solution :

The area of the rectangle is given by,

\text{Area}=\text{Length}\times \text{Breadth}

\text{Area}=x^2+8x+15

\text{Breadth}=x+3

x^2+8x+15=\text{Length}\times(x+3)

\text{Length}=\frac{x^2+8x+15}{x+3}

\text{Length}=\frac{(x+5)(x+3)}{x+3}

\text{Length}=x+5

Therefore, the length of the rectangle is x+5.

7 0
3 years ago
What are the zeros of the function?<br><br> h(x)=x3−2x2−3x<br><br> Select each correct answer.
Nat2105 [25]
Hello again!

It looks like you need a lot of help today. I'm glad I am able to help you!

h(x) = x³ - 2x² - 3x

The question you need to ask yourself is "How do you find the zeros of a function.

Answer: To find the zeros of a function, just set the function equal to zero then solve for x

x³ - 2x² - 3x = 0

Factor the left sides

x(x + 1)(x - 3) = 0

Now we can set factors equal to 0

x = 0 or x + 1 = 0 or x - 3 = 0

x = 0 or x = 0 - 1 or x = 0 + 3

x = 0 or x = -1 or x = 3

Thus,

The zeros of the function are: x = 0 or x = -1 or x = 3

As always, I am glad to help students like you!
8 0
3 years ago
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