What does Raoult's law state?
2 answers:
Correct Answer is A: <span> The vapor pressure of a pure solvent is higher than that of a solution containing that solvent.
Reason
According to Raoult's Law states that v</span><span>apor pressure of each component in the solution is equal to the vapor pressure of the pure component multiplied by its mole fraction. It is mathematically expressed as
P = X </span>
where, P = vapor pressure of solution
X = mole fraction of solute
P^{0} [/tex] = vapor pressure of pure component
Here X is always less than one (in solutions)
∴ P < P^{0} [/tex]
Reason
According to Raoult's Law states that v</span><span>apor pressure of each component in the solution is equal to the vapor pressure of the pure component multiplied by its mole fraction. It is mathematically expressed as
P = X </span>
where, P = vapor pressure of solution
X = mole fraction of solute
P^{0} [/tex] = vapor pressure of pure component
Here X is always less than one (in solutions)
∴ P < P^{0} [/tex]
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Answer:
Volume of water at this temperature is 27.2 mL
Explanation:
We know that
Here density of water is 0.992 g/mL
Here mass of water is 27.0 g
So
=
= 27.2 mL
Answer:
The new force will be \frac{1}{100} of the original force.
Explanation:
In the context of this problem, we're dealing with the law of gravitational attraction. The law states that the gravitational force between two object is directly proportional to the product of their masses and inversely proportional to the square of a distance between them.
That said, let's say that our equation for the initial force is:
And the force at this distance would be written in terms of the same equation:
Find the ratio between the final and the initial force:
Substitute the value for the final distance in terms of the initial distance:
Simplify:
This means the new force will be \frac{1}{100} of the original force.