What does Raoult's law state?
2 answers:
Correct Answer is A: <span> The vapor pressure of a pure solvent is higher than that of a solution containing that solvent.
Reason
According to Raoult's Law states that v</span><span>apor pressure of each component in the solution is equal to the vapor pressure of the pure component multiplied by its mole fraction. It is mathematically expressed as
P = X </span>
where, P = vapor pressure of solution
X = mole fraction of solute
P^{0} [/tex] = vapor pressure of pure component
Here X is always less than one (in solutions)
∴ P < P^{0} [/tex]
Reason
According to Raoult's Law states that v</span><span>apor pressure of each component in the solution is equal to the vapor pressure of the pure component multiplied by its mole fraction. It is mathematically expressed as
P = X </span>
where, P = vapor pressure of solution
X = mole fraction of solute
P^{0} [/tex] = vapor pressure of pure component
Here X is always less than one (in solutions)
∴ P < P^{0} [/tex]
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