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oksano4ka [1.4K]
2 years ago
11

How do you write 400000 in scientific notation?

Chemistry
2 answers:
Sidana [21]2 years ago
7 0
4x10^2 pls brainliest me
Andrej [43]2 years ago
6 0

Answer:

4 x 10 5

Explanation:

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There are many ___ about ghost ships &sea monsters
kirill115 [55]
Legends?? Jdjdhdhsn it needed 20 letter so... jdhdhhdnd
4 0
3 years ago
Two separate masses of zinc were measured on a laboratory balance. The first zinc had a sample mass of 210.10g, and the second z
wlad13 [49]

Answer:

Density is  7.15 g /mL.

Mass is  445.2 g.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Mass of first zinc sample = 210.10 g

Mass of second zinc sample = 235.10 g

Combined volume = 62.3 mL

Density of combined sample ?

Mass of combined sample = ?

Solution:

Mass of combined sample = 210.10 g + 235.10 g = 445.2 g

density = mass / volume

density = 445.2 g / 62.3 mL

density = 7.15 g /mL

3 0
3 years ago
A. 24.5 g of ammonia NH3 = how many moles of ammonia?
Art [367]
23.9 11.00 would be the wrong answer because I guessed
4 0
3 years ago
Differentiate the types of intermolecular forces
marshall27 [118]

Answer:

  1. Dipole interactions
  2. London dispersion forces
  3. Hydrogen bonds

Credit goes to: chem.libretexts.org

6 0
3 years ago
One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titrating a sample of silv
Flauer [41]

Answer:

1.1 × 10⁻⁴ M

Explanation:

Let's consider the following double displacement reaction.

CuCl₂(aq) + 2 AgNO₃(aq) → 2 AgCl(s)+ Cu(NO₃)₂(aq)

We can establish the following relations:

  • The molar mass of AgCl is 143.32 g/mol.
  • The molar ratio of AgCl to CuCl₂ is 2:1

The moles of CuCl₂ that reacted to produce 7.7 mg of AgCl are:

7.7 \times 10^{-3} gAgCl.\frac{1molAgCl}{143.32gAgCl} .\frac{1molCuCl_{2}}{2molAgCl} =2.7 \times 10^{-5}molCuCl_{2}

The molarity of CuCl₂ is:

M=\frac{2.7 \times 10^{-5}molCuCl_{2}}{0.250L} =1.1\times 10^{-4} M

7 0
3 years ago
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