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3 years ago

Can light cause the rubber to become solid? Why or why not? Does it matter what type of light she shines on the rubber?

Physics

1 answer:

ELEN [110]3 years ago

8 0

Answer:

Yes, ultraviolet light can turn a rubber into solid due to prolong exposure.

Explanation:

A rubber is a material with an elastic property, causing it to be deform by an external force but takes its shape when the force is removed. Light is an electromagnetic wave which causes the sensation of vision. It transfers energy to a medium during propagation through the medium.

Generally, most light do not cause hardness of a rubber. But an ultraviolet light can cause rubber to become solid over a period of time. This is possible if there is a prolong exposure of the rubber, and because of the evaporation of volatiles in the polymer material. Ultraviolet light are known to cause a rubber to become solid.

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Rainfall in tropical rainforests amounts to about 10 to 14 feet per year.

Savatey [412]

<u>Answer:</u>

The statement is true statement

<u>Explanation:</u>

Tropical rainforests are dry and green throughout the year. Even between the day and the night, temperatures don't change much. in tropical rainforests The average temperature varies from 70 to 85 °F (21 to 30 °C) .

Throughout tropical rainforests, the climate is quite wet, maintaining a humidity level of 77% to 88% year around which is a high value. The annual rainfall is between 80 and 400 inches (200 and 1000 cm), that is 6-33 feets, and it can rain heavily. It can drain as much as 5 cm (2 inches) in an hour.

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3 years ago

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a teacher studies how the number of absent affects the final grade of their students. what would be the dependent variable?

Mrrafil [7]

Answer:

Number of absent affects the grade

Explanation:

the dependent variable is the grade and the independent variable is the number of absent, since the grade depends of the number of absents.

8 0

3 years ago

The gravitational force between two objects is proportional to the square of the distance between the two objects.

Darina [25.2K]

Answer: True!

Explanation: The force is proportional to the square of the distance between 2 point masses

3 0

3 years ago

At a beach the light is generallypartially polarized owing to reflections off sand and water. At a particular beach on a particu

Ne4ueva [31]

Answer:

a) 0.159

b) 0.84

Explanation:

The Horizontal component is 2.3 times the vertical component

Let the horizontal electric field component = $E_{h}$

Let the vertical electric field component = $E_{v}$

The formula for light intensity is given by:

$I = \frac{E_{m} ^{2} }{2c \mu}$ ..............................(1)

$E_{m}$ is the resolution of the vertical and horizontal components, $E_{h} and E_{v}$

$E_{m} ^{2} = E_{h} ^{2} + E_{v} ^{2}$ ..................(2)

Light intensity before the glasses were put on:

$I_{1} = \frac{E_{m} ^{2} }{2c \mu_{1} }$ .............................(3)

Put equation (2) into equation (3)

$I_{1} = \frac{E_{h} ^{2} + E_{v} ^{2}}{2c \mu_{1} }$ .............................(4)

After the glasses were put on the horizontal component vanishes, i.e. $E_{h} = 0$

$I_{2} = \frac{ E_{v} ^{2}}{2c \mu_{2} }$ ...................................(5)

Divide equation (5) by equation (4)

$\frac{I_{2} }{I_{1} } = \frac{E_{v} ^{2} }{E_{h} ^{2} + E_{v} ^{2}}$ ...............................(6)

But $E_{h} = 2.3E_{v}$ ......................(7)

Insert equation (7) into (6)

$\frac{I_{2} }{I_{1} } = \frac{E_{v}^{2} }{(2.3E_{v})^{2} + E_{v} ^{2} } \\\frac{I_{2} }{I_{1} } = \frac{E_{v}^{2} }{5.29E_{v}^{2} + E_{v} ^{2} }\\\frac{I_{2} }{I_{1} } = \frac{E_{v}^{2} }{6.29E_{v}^{2} }\\\frac{I_{2} }{I_{1} } =\frac{1}{6.29} \\$