Answer:
The focus of Lesson 1 is Newton's first law of motion - sometimes referred to as the law of inertia. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
Answer:
Explanation:
When a standing wave is formed with six loops means the normal mode of the wave is n=6, the frequency of the normal mode is given by the expression:
Where is the length of the string and the velocity of propagation. Use this expression to find the value of .
The velocity of propagation is given by the expression:
Where is the desirable variable of the problem, the linear mass density, and is the tension of the cord. The tension is equal to the weight of the mass hanging from the cord:
With the value of the tension and the velocity you can find the mass density:
Explanation:
It is given that, the position of a particle as as function of time t is given by :
Let v is the velocity of the particle. Velocity of an object is given by :
So, the above equation is the velocity vector.
Let a is the acceleration of the particle. Acceleration of an object is given by :
At t = 0,
Hence, this is the required solution.
F = G*((m sub 1*m sub 2)/r^2)