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Natalka [10]
3 years ago
7

How does the ringing sound of a telephone travels from the phone to your ears?

Physics
1 answer:
Sedaia [141]3 years ago
6 0
The "ringing sound" are actually the soundwaves travelling from the phone to your ears.
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Imagine a particle that has three times the mass of the electron. All other quantities given above remain the same. What is the
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The only parameter that changes is mass m

It is only necessary to calculate the ratio Eh/Ee

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A small logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. The block is
harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

Where,

d_g = Depth of glass

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n_{air} = Refraction index of air

d_w = Depth of water

I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

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d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})

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Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

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