Given :
A 0.50-kg mass is attached to a spring of spring constant 20 N/m along a horizontal, frictionless surface.
The object oscillates in simple harmonic motion and has a speed of 1.5 m/s at the equilibrium position.
To Find :
At what location are the kinetic energy and the potential energy the same.
Solution :
Let, at location x from the equilibrium position the kinetic energy and the potential energy the same.
So,
Hence, this is the required solution.
Answer: D. 12 m/s
Explanation:
Use the formula of then just solve by inserting the numbers.
You use the first mountain height(5) and the second mountain height(12) and insert to the equation.
Sole and you'll be left with 12.
Add the labeling "m/s"
and youre done!
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Answer:
There are 5847.95 lines per cm for the grating.
Explanation:
Given that,
Wavelength of mercury line,
Angle in the third order spectrum,
Using the grating equation, we get :
Here, m = 3
Let there are N lines for the grating. So,
So, there are 5847.95 lines per cm for the grating.
We need the frequency of the photon, it is v = c/ λ
Where c is 3 x 10^8 ms^-1 and λ
is the wave length
We also need the expression of
connecting frequency to energy of photon
which is E = hv where h is Planck’s
constant
Combining the two equations
will give us:
E = h x c/λ
Inserting the values, we will
have:
E = 6.626 x 10^-34 x 3 x 10^8 /
0.126
E = 1.578 x 10^ -24 J
I attached a free body diagram for a better understanding of this problem.
We start making summation of Moments in A,
Then we make a summation of Forces in Y,
At the end we calculate the angle with the sin.