Answer:
-True - True - true - false -false - false
Explanation:
- True The flow depends only on the charge into the surface, not on the relative position
- True The two vectors are radial, so their relative direction do not changes
- True It just depends on the charge inside
- False, it only depends on the charge, not on the form from the integration surface
- False, because if it has a load inside it can be considered in the center, but if the load is outside the flow lines change direction with respect to the surface
- False The flow depends only on the load inside, not on its position
Answer:
Option B

Explanation:
Given information
Radius of container, r=12cm=12/100=0.12m
Angular velocity= 2 rev/s, converted to rad/s we multiply by 2π
Angular velocity, 
We know that speed, 
Centripetal acceleration,
and substituting
we obtain that

Substituting \omega for 12.56637061 and r for 0.12

Rounded off, 
Answer:
Portland normally had rainy, but mild winters. Yesterday it rained 0.75 inches in Portland.
Explanation:
This talks about the weather
W = _|....F*dx*cos(a)........With F=force, x=distance over which force acts on object,
.......0.............................and a=angle between force and direction of travel.
Since the force is constant in this case we don't need the equation to be an integral expression, and since the force in question - the force of friction - is always precisely opposite the direction of travel (which makes (a) equal to 180 deg, and cos(a) equal to -1) the equation can be rewritted like so:
W = F*x*(-1) ............ or ............. W = -F*x
The force of friction is given by the equation: Ffriction = Fnormal*(coeff of friction)
Also, note that the total work is the sum of all 45 passes by the sandpaper. So our final equation, when Ffriction is substituted, is:
W = (-45)(Fnormal)(coeff of friction)(distance)
W = (-45)...(1.8N).........(0.92).........(0.15m)
W = ................-11.178 Joules