The horizontal force is m*v²/Lh, where m is the total mass. The vertical force is the total weight (233 + 840)N.
<span>Fx = [(233 + 840)/g]*v²/7.5 </span>
<span>v = 32.3*2*π*7.5/60 m/s = 25.37 m/s </span>
<span>The horizontal component of force from the cables is Th + Ti*sin40º and the vertical component of force from the cable is Ta*cos40º </span>
<span>Thh horizontal and vertical forces must balance each other. First the vertical components: </span>
<span>233 + 840 = Ti*cos40º </span>
<span>solve for Ti. (This is the answer to the part b) </span>
<span>Horizontally </span>
<span>[(233 + 840)/g]*v²/7.5 = Th + Ti*sin40º </span>
<span>Solve for Th </span>
<span>Th = [(233 + 840)/g]*v²/7.5 - Ti*sin40º </span>
<span>using v and Ti computed above.</span>
Answer:
1.01 × 10⁵ Pa
Explanation:
At the surface, atmospheric pressure is 1.013 × 10⁵ Pa.
We need to find the total pressure on the air in the lungs of a person to a depth of 1 meter.
Pressure at a depth is given by :
Where
is the density of air, 
So,
Total pressure, P = Atmospheric pressure + 12 Pa
= 1.013 × 10⁵ Pa + 12 Pa
= 1.01 × 10⁵ Pa
Hence, the total pressure is 1.01 × 10⁵ Pa.
Answer:
The load that can be lifted is equal to the weight W = F2A1/A2
Explanation:
According to Pascal principle which states that the pressure applied to a liquid confined in a container will be transmitted equally to all other parts of the container.
Since pressure = Force/Area
The force F2 applied at one end of the piston will generate a pressure of F2/A2. This pressure generated will be transmitted to the other end of the piston of area A1 to lift the load through a distance.
The piston where the load is will experience an upward force F1 which is equal to Pressure × Area.
The pressure experienced by the load is applied by force F2.
Force on the load = (Pressure exerted by Force F2) × Area at the larger end A1
Force on the load = F2/A2 × A1
Since the load experiences a weight W
The weight will be equal to the force on the load which is to be lifted i.e W =Force on the load.
W = F2A1/A2
The load that can be lifted is equal to the weight W = F2A1/A2
