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Sindrei [870]
3 years ago
6

In Part I, the independent variable, the one that is intentionally manipulated, is blank.

Physics
2 answers:
Feliz [49]3 years ago
6 0

Answer: part 1 is mass and part 2 is density

Explanation: I just did it and got it right

BlackZzzverrR [31]3 years ago
5 0

answer

1. mass

2.speed

3.kinetic energy

just did it and got it correct

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How are energy, force, and the motion of objects related?
OLEGan [10]

Answer:

When two objects interact, each one exerts a force on the other that can cause energy to be transferred to or from the object. For example, when energy is transferred to an Earth-object system as an object is raised, the gravitational field energy of the system increases. This energy is released as the object falls; the mechanism of this release is the gravitational force. Likewise, two magnetic and electrically charged objects interacting at a distance exert forces on each other that can transfer energy between the interacting objects.

Explanation:

Even when an object is sitting still, it has energy stored inside that can be turned into kinetic energy (motion). ... A force is a push or pull that causes an object to move, change direction, change speed, or stop. Without a force, an object that is moving will continue to move and an object at rest will remain at rest.

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3 years ago
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which two tools below would be the most useful in testing how the mass of an object can affect the distance it moves after being
Mariulka [41]
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4 years ago
WILL GIVE BRAINLIEST
Diano4ka-milaya [45]

Answer:

nice to help you

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3 years ago
How does the work required to accelerate a particle from 10m/s to 20m/s compare to that required to accelerate it from 20m/s to
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The answer is B. It is the same..... hope this helps!

7 0
3 years ago
At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m2 . A fan is 30 m from the loudspea
marshall27 [118]

The concepts used to solve this problem are sound power, area of ear drum, and inverse square law.  First find the intensity I_2 using inverse square law for different distances. Then find the area of the ear drum using the diameter and finally find the energy transferred to each ear drum in one second. Intensity is inversely proportional to the square of the distance from the source:

I \propto \frac{1}{r^2}

Here,

r = Distance from the source,

\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}

I_2 = I_1 \frac{r_1^2}{r_2^2}

I_2 = (0.10W/m^2)(\frac{(1m)^2}{(30m)^2})

I_2 = 1.11*10^{-4}W/m^2

Now the expression for the Area of ear drum is

A= \frac{\pi d^2}{4}

A = \frac{\pi (8.4mm\frac{1m}{10^3mm})^2}{4}

A = 5.5*10^{-5}m^2

The expression for Sound power is

P = AI_2

Replacing,

P= (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)

P = 6.1*10^{-9}W = 6.1*10^{-9}J/s

Therefore the energy reached per second is 6.1*10^{-9}J

4 0
3 years ago
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