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Fudgin [204]
3 years ago
7

The solvent was propanone. Which of the three basic colours is most soluble in propanone?​

Chemistry
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

Red dye

Explanation:

In the given question, the complete question has not been provided but the propanone is used as a solvent in paper chromatography. The paper chromatography was performed for the black ink in which the black ink got separated in the red, blue and yellow colour.

From these three colours that are red, blue and yellow, the dye which is most soluble in propanone was red as red colour moved the most in the given chromatogram and the dye which travelled the most is most soluble in propanone.

Thus, red dye is the correct answer.

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Unit of measurement
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3 years ago
6. What's the structure of PF? Is it polar or non-polar?
charle [14.2K]

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4 0
3 years ago
Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these
deff fn [24]
The formation of nitric acid from nitrogen, hydrogen, and oxygen can be written as,

     N₂ + H₂ + 3O₂ --> 2HNO₃

The net enthalpy of formation of nitric acid is calculated by,
   Hrxn = Hproduct - Hreactant

Since all the reactants are in their elemental forms, the simplified equation would be,

    Hrxn = Hproduct 

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<em>Answer: -372.42 kJ</em>

7 0
3 years ago
Assuming 1 mol of Fe3+ and 2 mol of SCN- were allowed to react and reach equilibrium. 0.5 mol of product was formed. The total v
zaharov [31]

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a. 0.5 mol

b. 1.5 mol

c. 0.67

Explanation:

Fe3+ + SCN- -----> [FeSCN]2+

a. The ratio of the product to Fe3+ is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of Fe3+ was used. Leaving 0.5 mol remaining at equilibrium

b. The ratio of the product to SCN= is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of SCN- was used. Leaving 1.5 mol remaining at equilibrium

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3 0
3 years ago
4.81*10^24 atoms of lithium
enyata [817]

Answer:

Mass = 55.52 g

Explanation:

Given data:

Number of atoms of Li = 4.81×10²⁴ atom

Number of grams = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

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8 moles

Mass in gram:

Mass = number of moles × molar mass

Mass = 8 mol × 6.94 g/mol

Mass = 55.52 g

4 0
3 years ago
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