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vitfil [10]
3 years ago
5

You have nitrogen gas (N2) at a pressure of 0.5 atm, a volume of 25000 mL, and a temperature of 300 K, how many grams of nitroge

n are present?
Chemistry
1 answer:
Free_Kalibri [48]3 years ago
8 0

Answer:

About 7.109g

Explanation:

25000mL is the same as 25 liters.

PV=nRT \\\\0.5 (25)=n (0.0821) (300) \\\\n\approx 0.508

Multiplying this by the molar mass of nitrogen, you get about 7.109 grams of nitrogen. Hope this helps!

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Answer:

true

Explanation:

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Why is burning of plastics not considered a good method for their disposal?
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The equilibrium constant for the reaction 2NO2(g) N2O4(g) is Keq = . If a sample at equilibrium was found to contain 0.058 M NO2
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Answer:

\boxed{3.6}

Explanation:

                  2NO₂ ⇌ N₂O₄

E/mol·L⁻¹:   0.058     0.012

K_{\text{eq}} = \dfrac{\text{[N$_{2}$O$_{4}$]}}{\text{[NO$_{2}$]$^{2}$}} = \dfrac{0.012}{0.058^{2}} = \mathbf{3.6} \\\\

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Which compounds are classified as electrolytes and why?
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4 years ago
How many significant digits are in the number 2370.0?
xz_007 [3.2K]

Answer:

2370.0 contains 4 significant digits and Option (c) is correct .

1.20\times 10^{-3}\ contains\ three\ significant\ digit.

Option (b) is correct .

Step-by-step explanation:

Rules for finding significant digit .

1 : Non-zero digits are always significant.

2: Any zeros between two significant digits are significant .

3: Trailing zeros in the decimal number is also significant.

As the number given be 2,370.0.  

= \frac{23700}{10}

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1.20\times 10^{-3}\ contains\ three\ significant\ digit.

Option (b) is correct .

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3 years ago
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