Nucleus
Dna
Rna
Cell membrane
Mitochondria
Vacuoles
Matter
Nuclear membrane
Chemical bonds is the answer
Answer:- 171 g
Solution:- It asks to calculate the grams of sucrose required to make 1 L of 0.5 Molar solution of it.
We know that molarity is moles of solute per liter of solution.
If molarity and volume is given then, moles of solute is molarity times volume in liters.
moles of solute = molarity* liters of solution
moles of solute = 0.5*1 = 0.5 moles
To convert the moles to grams we multiply the moles by molar mass.
Molar mass of sucrose = 12(12) + 22(1) + 11(16)
= 144 + 22 + 176
= 342 grams per mol
grams of sucrose required = moles * molar mass
grams of sucrose required = 0.5*342 = 171 g
So, 171 g of sucrose are required to make 1 L of 0.5 molar solution.
Answer:
176984.38J
Explanation:
E = mC∆T
Where E is the energy in joules
M is the mass of water
C is the specific heat capacity of water =4.184J/g°C
It is known that it will take 4.184J of energy to change the temperature of water by one degree Celsius.
∆T = 98.6°c - 5.4°c
= 93.2°c
∆H = 454.3g × 4.18J/g°C × 93.2°c
= 176984.3768
176984.38J
