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frozen [14]
3 years ago
7

Which of the following statements apply to electric charges? please help this is the only question i need done!!

Physics
2 answers:
disa [49]3 years ago
8 0

The only correct statement on that list is <em>choice-C</em>:  If a positively charged rod is brought close to a positively charged object, the two objects will repel.

nekit [7.7K]3 years ago
5 0

Answer:

C. If a positively charged rod is brought close to a positively charged object, the two objects will repel.

Explanation:

According to coulomb's law, the magnitude of the electric force between two point charges at rest is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them. This force is repulsive for like charges and attractive for opposite charges.

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A spring with k = 500 N/m stores 704 J. How far is it extended from the equilibrium position
kaheart [24]

Given that:

k = 500 n/m,

work (W) = 704 J

spring extension (x) = ?

         we know that,

                      Work = (1/2) k x²

                          704 = (1/2) × 500 × x²

                            x = 1.67 m

A spring stretched for 1.67 m distance.

4 0
3 years ago
If the velocity of an airplane is doubled, then its kinetic energy<br> will increase by a factor of
ohaa [14]

Answer:4

Explanation:

3 0
3 years ago
I need help!!!!!!! Fast! I have to be done with this at 8:40!!!! Pleaseeeeeeee
kotegsom [21]
What you want.. you would need to post your question
8 0
3 years ago
In the laboratory, a ball is dropped onto a force-sensing platform several times, each time hitting a different surface (foam, f
NeX [460]

Answer:

Graphing the momentum against the change in moment yields a linear relationship.

Explanation:

This is an impulse experiment,

          I = ∫ F .dt

where the force and time of the collision are measured, therefore if we assume an average force the integral reduces to

           I = F t

Furthermore, the momentum is equal to the change in moment of the ball, this change in moment can be found using the energy relations measuring the height of the ball and calculating its speed, in the two intervals for the descent and for the exit, possibly the heights are different so the moment change is different from zero.

Starting point. Higher

          Em₀ = U = mgh

Lower end point, just before hitting the scale

          Em_{f} = K = ½ m v²

in the path in the air there is no friction

          Em₀ = Em_{f}

          m g h = ½ m v²

          v = \sqrt{2gh}

this height is different for the descent and ascent of the ball, so we have two moments

         Δp = p_{f} - p₀

         Δp = m (v_{f} -v₀)

         

therefore we have the relationship

         

         I = Δp

Graphing the momentum against the change in moment yields a linear relationship.

5 0
3 years ago
F a forklift raises a 76-kg load a distance of 2.5 m, about how much work has it done?
sleet_krkn [62]

W= FxD. Since the weight is not put into force you’re going to convert it by multiplying it by 9.8 (gravity). 76kg x 9.8 = 7448. Then multiply that by the distance (2.5). Your answer is 1862.

6 0
4 years ago
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