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worty [1.4K]
3 years ago
9

Which coordinate system would be most useful for two observers (one in Michigan and one in Florida) who wants to observe the sam

e astronomical object and discuss their observations over the phone as they’re making them?
a. celestial or azimuth-altitude


b. celestial


c. horizontal


d. azimuth-altitude
Physics
2 answers:
morpeh [17]3 years ago
4 0

Answer:

The answer is actually A: celestial

Explanation:

The answer is not azimuth-altitude because using that system means that the coordinates change with your geographic location. With celestial, you can coordinate the object's location using right ascension and declination no matter what latitude you are standing at.

Mkey [24]3 years ago
3 0

Answer : Celestial or azimuth - altitude

Explanation :  

Celestial : The celestial coordinates that are analogous to longitude and latitude are called RA and Dec.

RA = Right Ascension

Dec = Declination

RA is the measured in unit of time and Dec is measured in degree.

The equatorial coordinate system is the projection of the latitude and longitude coordinate system on the celestial sphere.

Azimuth - altitude :  Azimuth - altitude define the location of an object in the sky.

The altitude is the distance of an object appears to be above the horizon.

The Azimuth of the object is the angular distance  along the horizon to the location of the object.

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lara [203]

Answer:

compression of spring is x = 0.12 m

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Explanation:

Given:

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How much are the springs compressed?

Solution:

- Using equilibrium equation on the taptap in vertical direction:

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- Compute the force due to all the weights on the taptap:

                                F_weight = (n_p*m_p + n_g*m_g + n_c*m_c + m_b)*9.81

                                F_weight = (69*27 + 3*15 + 5*3 + 25)*9.81  

                                F_weight = 19109.88 N

- The restoring force of a spring is given by:

                                F_spring = k*x

Where, k is the spring stiffness and x is the displacement:

                                 F_weight = F_spring

                                 19109.88 = k*x

                                 x = 19109.88 / k

We need to assume the spring stiffness we will take k = 160,0000 N/m (trucks suspension systems). The value of the stiffness must be high enough to sustain a load of 1.911 tonnes.

                                 x = 19109.88 / 160,000

                                 x = 0.1194 m ≈ 0.12 m = 12 cm

- A compression of 12 cm seems reasonable for a taptap to carry 1.911 tonnes of load. Hence, the assumption of spring stiffness was reasonable. Hence, the compression of spring is x = 0.12 m.

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