Complete question:
The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.
Answer:
The exit velocity is 629.41 m/s
Explanation:
Given;
initial temperature, T₁ = 1200K
initial pressure, P₁ = 150 kPa
final pressure, P₂ = 80 kPa
specific heat at 300 K, Cp = 1004 J/kgK
k = 1.4
Calculate final temperature;
k = 1.4
Work done is given as;
inlet velocity is negligible;
Therefore, the exit velocity is 629.41 m/s
The candle is giving off light
Chemical energy from the candle is converted to thermal energy
It increases across a period but it decreases down a group.
Answer:
Linear motion is a one-dimensional motion along a straight line, and can therefore be described mathematically using only one spatial dimension.
Explanation:
Answer:
When light incident at angle more than critical angle then whole beam of light will get reflected at same angle into the same medium
So correct answer is
Option D
Explanation:
Critical angle is the maximum angle of incidence for which light shows the phenomenon of refraction of light
Here light bends at 90 degree angle when light incident at critical angle
Now if the incident light is more than the critical angle then light will follow the rules of reflection and all light rays will get reflected at same angle as that of angle of incidence
So here we can say that correct answer is
Option D
