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VashaNatasha [74]
3 years ago
12

Calculate the number of atoms in a 7.45x10^3 g sample of sodium

Chemistry
1 answer:
Whitepunk [10]3 years ago
7 0

The molecular mass of sodium = 23g


One mole of sodium consists of 23 g of sodium


One mole consists of 1 Avagadro(6.022 x 10^23 molecules) number of molecules

Therefore 23 g consists of 6.022 x 10^23 molecules of Sodium.

Hence 7.45 x 10^3 g of Sodium will consist of x no of molecules of sodium.

x no of molecules =

(7.45 x 10^3 g/23 g) x (6.022 x 10^23)

=1950.6 x 10^ 23 molecules (atoms).

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What is indirect evidence in science
hodyreva [135]

Definition of indirect evidence. : evidence that establishes immediately collateral facts from which the main fact may be inferred : circumstantial evidence.

8 0
3 years ago
Water is a good solvent when A) the solute is hydrophobic. B) the solute is nonpolar. C) the solute is polar. D) the solvent is
pochemuha

the answer is C. the solute polar  water itself is a polar solvent so it combines well with other polar solvents (which basically have polar molecules)

8 0
3 years ago
Water is placed in a graduated cylinder and the volume is recorded as 43.5 mL. A homogeneous sample of metal pellets with a mass
Ipatiy [6.2K]

Answer:

1.8g

Explanation:

Initial volume = 43.5ml

Final volume = 49.4ml

Mass = 10.88g

Density = ?

Volume = Final volume - initial volume

= 49.4 - 43.5

= 5.9ml

Density = Mass/volume

Density = 10.88/5.9

= 1.8g/ml

4 0
4 years ago
Balance the following
olga55 [171]

Answer:

Your coefficients (the numbers in front of the molecule) will be the following from left to right.

1. <u>1 - 2 - 1 - 2</u>

2. <u>2 - 1 - 2 - 2 - 1</u>

3. <u>2 - 4 - 1</u>

4. <u>2 - 4 - 3</u>

5. <u>2 - 2 - 2 - 1</u>

6. <u>1 - 1 - 1</u>

7. <u>2 - 1 - 2</u>

8. <u>3 - 1 - 2 - 3</u>

9. <u>3 - 1 - 2 - 3</u>

10. <u>2 - 1 - 1 - 1</u>

Explanation:

To balance this equations first count how many times an element is on each side and then see what needs to be changed in order to balance them.

8 0
1 year ago
Calculate the vapor pressure at 25 ?c of hexane above the solution. the vapor pressure of pure hexane at 25 ?c is 151 torr.
Studentka2010 [4]
One of the many ways in order to solve for the vapor pressure of pure components at a given temperature is through the Antoine's equation which is written below,
                                    P = 10^(A - B/C+T)
where A, B, and C are constants and T is the temperature in °C and P is the vapor pressure in mm Hg. 
For hexane,
                             A = 7.01
                             B = 1246.33
                             C = 232.988

Substituting the known values,
                            P = 10^(7.01 - 1246.33/232.988+25)
                             <em> P = 151.199 mm Hg</em>
8 0
4 years ago
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