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VashaNatasha [74]
3 years ago
12

Calculate the number of atoms in a 7.45x10^3 g sample of sodium

Chemistry
1 answer:
Whitepunk [10]3 years ago
7 0

The molecular mass of sodium = 23g


One mole of sodium consists of 23 g of sodium


One mole consists of 1 Avagadro(6.022 x 10^23 molecules) number of molecules

Therefore 23 g consists of 6.022 x 10^23 molecules of Sodium.

Hence 7.45 x 10^3 g of Sodium will consist of x no of molecules of sodium.

x no of molecules =

(7.45 x 10^3 g/23 g) x (6.022 x 10^23)

=1950.6 x 10^ 23 molecules (atoms).

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3 years ago
if i add 25 ml of water to 135 ml of a 0.25 M NaOH solution what will the molarity of the diluted solution be​
DENIUS [597]

Answer:

0.21 M. (2 sig. fig.)

Explanation:

The molarity of a solution is the number of moles of the solute in each liter of the solution. The unit for molarity is M. One M equals to one mole per liter.

How many moles of NaOH in the original solution?

n = c \cdot V,

where

  • n is the number of moles of the solute in the solution.
  • c is the concentration of the solution. c = 0.25 \;\text{M} = 0.25\;\text{mol}\cdot\textbf{L}^{-1} for the initial solution.
  • V is the volume of the solution. For the initial solution, V = 135\;\textbf{mL} = 0.135\;\textbf{L} for the initial solution.

n = c\cdot V = 0.25\;\text{mol}\cdot\textbf{L}^{-1} \times 0.135\;\textbf{L} = 0.03375\;\text{mol}.

What's the concentration of the diluted solution?

\displaystyle c = \frac{n}{V}.

  • n is the number of solute in the solution. Diluting the solution does not influence the value of n. n = 0.03375\;\text{mol} for the diluted solution.
  • Volume of the diluted solution: 25\;\text{mL} + 135\;\text{mL}  = 160\;\textbf{mL} = 0.160\;\textbf{L}.

Concentration of the diluted solution:

\displaystyle c = \frac{n}{V} = \frac{0.03375\;\text{mol}}{0.160\;\textbf{L}} = 0.021\;\text{mol}\cdot\textbf{L}^{-1} = 0.021\;\text{M}.

The least significant number in the question comes with 2 sig. fig. Keep more sig. fig. than that in calculations but round the final result to 2 sig. fig. Hence the result: 0.021 M.

8 0
3 years ago
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From the balanced equation of the reaction:

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More on stoichiometric calculations can be found here: brainly.com/question/8062886

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