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katen-ka-za [31]
3 years ago
6

In the tollowing combustion reaction of acetylene (C2H2), how many lters of CO2 will be produced it 60 liters of 02 is used, giv

en that both gases are at STP?
Chemistry
1 answer:
Nina [5.8K]3 years ago
8 0

Under STP 1 mol of gas has volume 22.4 L.

2C2H2 + 5O2 ------> 4CO2 + 2H2O

from reaction 5*22.4 L 4 *22.4L

given 60L x L

x=(60*4 *22.4)/5*22.4 = (60*4)/5 =48 L of CO2

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Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

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<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
What would happen if an alkali metal was combined with a halogen?explain ​
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Answer:

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Explanation:

6 0
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Answer:

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Net ionic equation

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\boxed{\rm 3Ca^{2+} + 2PO_{4}^{3-} \longrightarrow Ca_{3}(PO_{4})_{2}}

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