Empirical formula mass
Molecular fornula mass:-180g/mol
- n=Molecular formula mass/Empirical formula mass
- m=180/30
- n=6
Molecular formula:-
- n×Empirical formula
- 6(CH_2O
- C_6H_12 O_6
I believe the answer is 65.254%
Answer:
1.2 x 10⁵ moles Ag (2 sig. figs.)
Explanation:
1 mole any substance (elements or compounds) => 6.023 x 10²³ particles of specified substance
∴ 6.9 x 10²⁸ atoms Ag = 6.9 x 10²⁸ Ag atoms / 6.023 x 10²³ Ag atoms/mole Ag
= 1.145608501 x 10⁵ moles Ag (calculator answer)
= 1.2 x 10⁵ moles Ag (2 sig. figs.)
Answer:
Their identity changes in both Reaction A and Reaction B.