Answer:
Higher K at very high temperatures.
Explanation:
It is inferred is K is significantly greater at very high temperatures, allowing high production at low cost.
The "Van Gogh" one is subjective, because it expresses opinion and is not a true, hard fact. :)
B.) At higher temperature and low pressure.
Hope this helps you.
Answer:
pH= 11.5
Explanation:
To the calculation of the <u>pH value</u>, we need to write the ionization equation first. Then using the <u>ICE table</u> and the information given by the problem we can set up the problem:

I 1.1 M Zero Zero
C -X +X +X
E 1.1-X X X
As next step, using the <u>equilibrium expression</u> for Kb we can replace the terms find in the ICE table and then <u>solve for X</u>, so:
![Kb=\frac{[C_4H_4N_2O_3NH_3^+][OH^-]}{[C_4H_4N_3O_3NH_2]}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BC_4H_4N_2O_3NH_3%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BC_4H_4N_3O_3NH_2%5D%7D)
![9.2x10^-^6=\frac{[X][X]}{[1.1-X]}](https://tex.z-dn.net/?f=9.2x10%5E-%5E6%3D%5Cfrac%7B%5BX%5D%5BX%5D%7D%7B%5B1.1-X%5D%7D)

![(9.2x10^-^6)*[1.1-X]=X^2](https://tex.z-dn.net/?f=%289.2x10%5E-%5E6%29%2A%5B1.1-X%5D%3DX%5E2)


With the value of X we can find the <u>pOH</u> (lets remember that X<u> is the concentration of OH-</u>), so:


Finally, we can find the <u>pH value</u> with the equation:




<u>The 1.1 M allantoin solution have a pH value of 11.5</u>