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Troyanec [42]
3 years ago
7

A kinesin that is transporting a secretory vesicle uses approximately 80 ATP molecules/s. Each ATP provides a kinesin molecule w

ith an energy of about 0.8 × 10-19 J. If the velocity of the kinesin is 800 nm/s, can you determine the force the kinesin is exerting, if you assume that all the ATP energy is used (100% efficiency)? If you can, find it and give your answer in newtons. If not, answer with 0.
Physics
1 answer:
Firdavs [7]3 years ago
7 0

Answer:

The force is  F  =   8*10^{-12} \ N

Explanation:

From the question we are told that

     The rate at which ATP molecules are used is R =  80 ATP/ s

       The energy provided by a single ATP is  E_{ATP} =  0.8 *  10^{-19} J

       The velocity of the kinesin is  v  =  800 nm/s =  800*10^{-9} m/s

The power provided by the ATP in one second is  mathematically represented as

       P =  E_{ATP}  *  R

substituting values

       P =  80 * 0.8*10^{-19 }

       P =  6.4 *10^{-18}J/s

Now  this power is mathematically represented as

       P  =  F *  v

Where  F  is  the force the kinesin is exerting

  Thus  

          F  =   \frac{P}{v}

substituting values

            F  =   \frac{6.4*0^{-18}}{800 *10^{-9}}

           F  =   8*10^{-12} \ N

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