Answer:
the speed of the car at the top of the vertical loop 
the magnitude of the normal force acting on the car at the top of the vertical loop 
Explanation:
Using the law of conservation of energy ;
The magnitude of the normal force acting on the car at the top of the vertical loop can be calculated as:
![F_{N} = \frac{mv^2_{top}}{R} \ - mg\\\\F_{N} = \frac{m(2.0 \sqrt{gR})^2}{R} \ - mg\\\\F_{N} = [(2.0^2-1]mg\\\\F_{N} = [(2.0)^2 -1) (50*10^{-3} \ kg)(9.8 \ m/s^2]\\\\](https://tex.z-dn.net/?f=F_%7BN%7D%20%3D%20%5Cfrac%7Bmv%5E2_%7Btop%7D%7D%7BR%7D%20%5C%20-%20mg%5C%5C%5C%5CF_%7BN%7D%20%3D%20%5Cfrac%7Bm%282.0%20%5Csqrt%7BgR%7D%29%5E2%7D%7BR%7D%20%5C%20-%20mg%5C%5C%5C%5CF_%7BN%7D%20%3D%20%5B%282.0%5E2-1%5Dmg%5C%5C%5C%5CF_%7BN%7D%20%3D%20%5B%282.0%29%5E2%20-1%29%20%2850%2A10%5E%7B-3%7D%20%5C%20kg%29%289.8%20%5C%20m%2Fs%5E2%5D%5C%5C%5C%5C)
<span>A transverse wave is characterized by peaks and dips.</span>
Answer:
Explanation:
Given that,
The instantaneous current in the circuit is giveen by :
We need to find the rms value of the current.
The general equation of current is given by :
It means, 
We know that,
So, the rms value of current is 2.12 A.
<span>During which lunar phase is the moon's far side entirely lit?</span><span>
"Near side entirely lit" means we see the whole side facing us. The moon looks like a complete circle.
Hope This Helped! :3</span>
Pressure is defined as the force applied per unit area of the press. In this case, we are given with a force equivalent to 350 N and an area equal to 4 cm2. 4 cm2 is equal to 0.0004 m2. We divide 350Newton by 0.0004 square meters equal to 875,000 Pascals or 875 kiloPascals.
