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lukranit [14]
3 years ago
7

An olympic hurdler accelerates at a rate of 15.5 m/s2 . what is the rate in miles/min2 ?

Physics
2 answers:
Alborosie3 years ago
6 0

Answer: 34.68 mile/min^2

Explanation:

1 mile = 1609 meter

1 min = 60 s then squared will be 3600s

Mile/min^2 = 2.24

Give 15.5m/s^2

We multiply

15.5 by 2.24

= 34.68 mile/min^2

Wittaler [7]3 years ago
5 0
You have to use conversion units for this. For every 1 mile, there is an equivalent amount of 1,609 meters. For every 1 minute, there is an equivalent amount of 60 seconds. Using the dimensional analysis approach, the solution is as follows:

Acceleration = 15.5 m/s²*(1 mile/1,609 m)*(60 s/1 min)² = 34.68 miles/min²
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3 years ago
In nature, where do fusion reactions take place?
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If two positive charges are near each other they will repel each other.
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3 years ago
The escape velocity of any object from Earth is 11.2 km/s. (a) Express this speed in m/s and km/h. (b) At what temperature would
natima [27]

Answer:

a ) 11.1 *10^3 m/s = 39.96 Km/h

b) T_{o2} =1.58*10^5 K

Explanation:

a)v_{es} =v_{rms}= 11.1 km/s =11.1 *10^3 m/s = 39.96 Km/h

b)

M_O2 = 32.00 g/mol =32.0*10^{-3} kg/mol

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v_{rms} = \sqrt{ \frac{3RT}{M}}

So, v_{rms,o2} =\sqrt{ \frac{3RT_{o2}}{M_{o2}}}

multiply each side by M_{o2}, so we have

v_{rms,o2}^2 *M_{o2} =3RT_{o2}

solving for temperature T_{o2}

T_{o2} = \frac{v_{rms,o2}^2 *M_{o2}}{3R}

In the question given,v_{rms} =v_{es}

T_{o2} = \frac{(11.1*10^3)^2 *32.0*10^{-3}}{3*8.31}

T_{o2} =1.58*10^5 K

7 0
3 years ago
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GREYUIT [131]

Answer:  Option B

Explanation:

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This particles or sediments then gets compacted and lithified in due course of time, and forms sedimentary rocks.

Water is also needed to undergo metasomatism process, that creates a metamorphic rock.

Hence, water flow is also an important driving force in rock cycle, along with tectonic activities.

Thus, the correct answer is option (B).

4 0
3 years ago
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