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il63 [147K]
3 years ago
11

A planet with a mass one-half that of Earth has a radius that is 3 times that of Earth's radius. What is the gravitational field

strength of the planet?
Physics
1 answer:
stiv31 [10]3 years ago
6 0

The gravitational acceleration of a planet is proportional to the planet's mass, and inversely proportional to square of the planet's radius.

So when you stand on the surface of this particular planet, you feel a force of gravity that is

(1/2) / (3²)

of the force that you feel on the surface of the Earth.

That's <em>(1/18)</em> as much as on Earth.

The acceleration of gravity there would be about <em>0.545 m/s²</em>.  

This is about 12% less than the gravity on Pluto.

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Determine the gain in the potential energy when a 8.0 kg box is raised 17.2 m.
Marysya12 [62]

Answer:

<h2>The answer is 1376 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 8 × 10 × 17.2

We have the final answer as

<h3>1376 J</h3>

Hope this helps you

6 0
3 years ago
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Finger [1]

Answer:

<em>U = 66,150 J</em>

Explanation:

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Gravitational potential energy is the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8\ m/s^2.

The child of mass m=45 Kg is perched above a h=150 m ravine. His gravitational potential energy is:

U=45~Kg\cdot 9.8\ m/s^2\cdot 150\ m

U = 66,150 J

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3 years ago
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Explanation:

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Dmitrij [34]

Answer:

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Explanation:

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ziro4ka [17]

Answer:

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Explanation:

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