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il63 [147K]
3 years ago
11

A planet with a mass one-half that of Earth has a radius that is 3 times that of Earth's radius. What is the gravitational field

strength of the planet?
Physics
1 answer:
stiv31 [10]3 years ago
6 0

The gravitational acceleration of a planet is proportional to the planet's mass, and inversely proportional to square of the planet's radius.

So when you stand on the surface of this particular planet, you feel a force of gravity that is

(1/2) / (3²)

of the force that you feel on the surface of the Earth.

That's <em>(1/18)</em> as much as on Earth.

The acceleration of gravity there would be about <em>0.545 m/s²</em>.  

This is about 12% less than the gravity on Pluto.

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The five planets that you can see from Earth without a telescope are Mercury, Venus, Mars, Jupiter and Saturn. 
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3 years ago
A vitamin called folic acid is very important for neural tube development, which is the development of the baby's
Anestetic [448]

Answer:

Explanation:

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3 0
3 years ago
Determine the value of the resistor r so that a current of 0.5a flows through the load.
iren2701 [21]
What is the value of the voltage? There must be one somewhere.

This might be too simple minded, but I'll give it a voltage of 10 Volts.

R = voltage / Current
R = 10 / 0.5
R = 20 volts. 

Perhaps you could post a diagram if this is a Kirchhoff Law Question.
8 0
3 years ago
A 30.0 kg packing case is initially at rest on the floor of a 1500 kg pickup truck. The coefficient of static friction between t
alexgriva [62]

Answer:

(a). The magnitude of the frictional force acting on the case is 66 N northward.

(b). The magnitude of the friction force acting on the case is 58.8 N southward.

Explanation:

Given that,

Mass of packing case = 30.0 kg

Mass of truck = 1500 kg

Coefficient of static friction = 0.30

Coefficient of kinetic friction = 0.20

Acceleration = 2.20 m/s² northward

(A). We need to calculate the force acting on the case

Using formula of force

F=ma

Put the value into the formula

F=30.0\times2.20

F=66\ N

We need to calculate the maximum static frictional force

Using formula of frictional force

f_{\mu}=\mu mg

Put the value into the formula

F_{\mu}=0.30\times30.0\times9.8

F_{\mu}=88.2

The frictional force is greater then the force acting on the block

Then, The frictional force is 66 N northward.

(B). We need to calculate the force acting on the case

Using formula of force

F = ma

Put the value into the formula

F=30.0\times3.40

F=102\ N

The static friction force is less then the force action on the case

We need to calculate the maximum static frictional force

Using formula of frictional force

f_{\mu}=\mu mg

f_{\mu}=0.20\times30.0\times9.8

f_{\mu}=58.8\ N

So, The magnitude of the friction force acting on the case is 58.8 N southward.

Hence, This is the required solution.

7 0
3 years ago
Describe how our knowledge of science changes over time
MA_775_DIABLO [31]

Answer:

Explanation:

Science has come a long way in the last 150 years. We now have more powerful data analysis techniques, more sophisticated equipment for making observations and running experiments, and a much greater breadth and depth of scientific knowledge.

6 0
2 years ago
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