Answer:
The coefficient of static friction between your partner and the floor is 0.55
Explanation:
Given:
Mass
Kg
Frictional force
N
From the formula of frictional force,

Where
coefficient of static friction, 
Put the above values and find the coefficient of static friction.


Therefore, the coefficient of static friction between your partner and the floor is 0.55
Answer:
In a concave mirror, if an object is located between the center of curvature and the focal point, what is the best way to describe the image formed? Real, inverted, and smaller than the object. Real, inverted, and larger than the object. light rays travel parallel to each other, no other image is formed.
Hedndjf Hinduism’s jeirbduddn dudurnidkd idbehdududid idjdjdudud idjdbdudud idisjdbdbd
Answer
given,
mass of the = m₁ = 8.75 Kg
another mass of the object = m₂ = 14 Kg
distance between them = 50 cm
R₁ = 17 cm
R₂ = 50 -17 = 33 cm
a) Force applied due to the Mass 8.75 in +ve x- direction



Force applied due to mass 14 Kg in -ve x-direction



net force
F = F₁ + F₂


Using newton second law



b) As the acceleration of mass comes out to be +ve hence, the direction will be toward the mass of 8.75 Kg