After x seconds, an object will fall
![\frac{1}{2}at^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dat%5E2)
where a is acceleration due to gravity and t is time
so when t=3.3
the distance it will fall is
![(\frac{1}{2})(9.8\frac{m}{s^2})(3.3m)^2](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B2%7D%29%289.8%5Cfrac%7Bm%7D%7Bs%5E2%7D%29%283.3m%29%5E2)
=53.361m
it will fal 53.361 meters
Answer:Principle of rectilinear propagation of light
Explanation:Principle of rectilinear propagation of light
Rectilinear propagation of light refers to the propensity of light to travel along a straight line without any interference in its trajectory. ... It is because light travels along a straight line and leaves only the areas where the object interferes.
Answer:
Explanation:
The formula for gravitational potential energy is
Ep = m · g · h Assuming that the acceleration is g = 10m/s²
Ep = 45.4 · 10 · 21.9 = 9,942.6 J
God is with you!!!
Answer:
c. about 1/10 as great.
Explanation:
While jumping form a certain height when we bend our knees upon reaching the ground such that the time taken to come to complete rest is increased by 10 times then the impact force gets reduced to one-tenth of the initial value when we would not do so.
This is in accordance with the Newton's second law of motion which states that the rate of change in velocity is directly proportional to the force applied on the body.
Mathematically:
![F\propto\frac{d}{dt} (p)](https://tex.z-dn.net/?f=F%5Cpropto%5Cfrac%7Bd%7D%7Bdt%7D%20%28p%29)
![\Rightarrow F=\frac{d}{dt} (m.v)](https://tex.z-dn.net/?f=%5CRightarrow%20F%3D%5Cfrac%7Bd%7D%7Bdt%7D%20%28m.v%29)
since mass is constant
![F=m\frac{d}{dt}v](https://tex.z-dn.net/?f=F%3Dm%5Cfrac%7Bd%7D%7Bdt%7Dv)
when ![dt=10t](https://tex.z-dn.net/?f=dt%3D10t)
then,
![F'=m.\frac{v}{10\times t}](https://tex.z-dn.net/?f=F%27%3Dm.%5Cfrac%7Bv%7D%7B10%5Ctimes%20t%7D)
![F'=\frac{1}{10} \times \frac{m.v}{t}](https://tex.z-dn.net/?f=F%27%3D%5Cfrac%7B1%7D%7B10%7D%20%5Ctimes%20%5Cfrac%7Bm.v%7D%7Bt%7D)
the body will experience the tenth part of the maximum force.
where:
represents the rate of change in dependent quantity with respect to time
momentum
mass of the person jumping
velocity of the body while hitting the ground.
Answer:
A “frame of reference” is a standard relative to which motion and rest may be measured; any set of points or objects that are at rest relative to one another enables us, in principle, to describe the relative motions of bodies.
Explanation:
When you see a ball roll down a street, you can tell the ball is moving because the frame of reference is the streets, whatever may be on the side of the roads, or the Earth. All of these are frames of reference. All measurements of motion will be compared to a frame of reference.