Ok so this is a kinetic and potential energy problem. KE= 1/2*m*v^2 and PE= mgh so we set them equal to each other and get KE=PE so 1/2mv^2=mgh so mass divers out and left with 1/2v^2 =gh so solving for h or height we get
h=(1/2v^2)/g so h= 1/2*(6.5m/s)^2/9.80m/s^2 = 2.16m in height the ball will reach.
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Answer:
A. The box experiences more friction on the carpeted floor
Explanation:
Friction is the force that opposes the motion of an object when it slides along a surface. The magnitude of the friction is given by
where m is the mass of the object, g is the acceleration due to gravity, and 
is the coefficient of friction, which depends on the type of material of the surface: the larger this coefficient, the stronger the friction, the more difficult is to push the box along the surface. Generally, a smooth surface has a lower coefficient of friction, while a rough surface has a larger coefficient of friction.
In this case, Ethan find it easier to push the box on the marble floor, because marble is smoother than the carpet and so friction is weaker, while for the carpeted floor the coefficient of friction is larger and so the friction is stronger, making it more difficult to push the box.
Answer:
Final velocity of ball = 20 m/s
Explanation:
Given:
Height when ball released = 20meter
Find;
Time taken to fall
Final velocity of ball
Computation:
Initial velocity of ball = 0 m/s
Acceleration due to gravity = 10 m/s²
Using equation of motion;
S = ut + (1/2)(g)(t²)
20 = (0)(t) + (1/2)(10)(t²)
20 = 5(t²)
(t²) = 20 / 5
(t²) = 4
Time taken to fall = 2 second
V = u + at
V = 0 + (10)(2)
Final velocity of ball = 20 m/s
