Answer:
The force per unit length (N/m) on the top wire is 16.842 N/m
Explanation:
Given;
distance between the two parallel wire, d = 38 cm = 0.38 m
current in the first wire, I₁ = 4.0 kA
current in the second wire, I₂ = 8.0 kA
Force per unit length, between two parallel wires is given as;
where;
μ₀ is constant = 4π x 10⁻⁷ T.m/A
Substitute the given values in the above equation and calculate the force per unit length
Therefore, the force per unit length (N/m) on the top wire is 16.842 N/m
1) Potential difference: 1 V
2)
Explanation:
1)
When a charge moves in an electric field, its electric potential energy is entirely converted into kinetic energy; this change in electric potential energy is given by
where
q is the charge's magnitude
is the potential difference between the initial and final position
In this problem, we have:
is the magnitude of the charge
is the change in kinetic energy of the particle
Therefore, the potential difference (in magnitude) is
2)
Here we have to evaluate the direction of motion of the particle.
We have the following informations:
- The electric potential increases in the +x direction
- The particle is positively charged and moves from point a to b
Since the particle is positively charged, it means that it is moving from higher potential to lower potential (because a positive charge follows the direction of the electric field, so it moves away from the source of the field)
This means that the final position b of the charge is at lower potential than the initial position a; therefore, the potential difference must be negative:
Answer: Partial pressure of nitrogen and xenon are 288mmHg and 548 mmHg respectively.
Explanation:
The partial pressure of a gas is given by Raoult's law, which is:
where,
= partial pressure of substance A
= total pressure
= mole fraction of substance A
We are given:
Mole fraction of a substance is given by:
And,
Mole fraction of nitrogen is given as:
Molar mass of = 28 g/mol
Molar mass of = g/mol
Putting values in above equation, we get:
To calculate the mole fraction of xenon, we use the equation:
Thus partial pressure of nitrogen and xenon are 288mmHg and 548 mmHg respectively.
The magnitude of the displacement current between the plates is
Given,
A=4.3*
=
*A*
=
= -=
An electrical charge carrier flow known as current often involves electrons or atoms lacking in electrons. The capital letter I is frequently used as a symbol for current. Amperes are the common unit and are denoted by the letter A. A coulomb of electrical charge moves past a certain place in one second as one ampere of current does. Franklin current or conventional current are terms used by physicists to describe how current flows from relatively positive to comparatively negative sites. Negatively charged electrons are the most prevalent charge carriers. They move in a somewhat good direction from relatively negative points.
With e in volts per meter and t in seconds. at t = 0, the field is upward. the plate area is 4. 3 × 10-2 m2. for t > 0, what is the magnitude of the displacement current between the plates?
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