1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
barxatty [35]
2 years ago
6

Pls answer these questions I beg u!! And use the diagram for answering the questions pls help!! I will make u the BRAINLIEST!!!

Physics
1 answer:
MA_775_DIABLO [31]2 years ago
3 0
I think this is the answer:

<span>Matter can change its state because of the pressure and/or the temperature.</span>
You might be interested in
PLZ HELP ITS A TIMED TEST!!!!!!!!!!!!!!!!
sergij07 [2.7K]
Image #3 good luck!!!!!!!!!!!
7 0
3 years ago
A farmer had 15 sheep, and all but 8 died. How many are left?
Troyanec [42]
So he has 7 sheepleft if i did it correctly
15-8=7
3 0
2 years ago
Read 2 more answers
A pure substance has a/an
Evgesh-ka [11]

Answer:

Element or a compound.

Explanation:

6 0
3 years ago
A 16.0kg canoe moving to the left at 12.5m/s makes an elastic head-on collision with a 14.0kg raft moving to the right at 16.0m/
kherson [118]

The canoe is moving at 14.1 m/s to the right after the collision.

Explanation:

According to the law of conservation of momentum, in absence of external forces the total momentum of the system must be conserved before and after the collision. So we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 16.0 kg is the mass of the canoe

u_1 = -12.5 m/s is the initial velocity of canoe (we take right as positive direction, and since the canoe is moving to the left, its velocity is negative)

v_1 is the final velocity of the canoe

m_2 = 14.0 kg is the mass of the raft

u_2 = +16.0 m/s is the initial velocity of the raft

v_2 = -14.4 m/s is the final velocity of the raft

Re-arranging the equation and substituting the values, we find: the final velocity of the canoe:

v_1 = \frac{m_1 u_1 + m_2 u_2-m_2 v_2}{m_1}=\frac{(16.0)(-12.5)+(14.0)(16.0)-(14.0)(-14.4)}{16.0}=+14.1 m/s

So, the canoe is moving at 14.1 m/s to the right after the collision.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

5 0
3 years ago
How are the planets sizes related to their surface gravity
dexar [7]

Answer:

The surface gravity is inversely proportional to the square of the radius of the planet

Explanation:

The gravity at the surface of a planet is given by:

g=\frac{GM}{R^2}

where

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

We see from the formula that the surface gravity is inversely proportional to the square of the radius of the planet, R.

At the Earth's surface, the value of the surface gravity is approximately 9.81 m/s^2.

6 0
2 years ago
Other questions:
  • Which organisms develop gills from pharyngeal arches and later develop lungs to breathe on land
    7·2 answers
  • A football game begins with a coin toss to determine who kicks off. The referee tosses the coin upward with an initial speed of
    11·1 answer
  • Describe two ways unbalanced forces help you in your day to<br> day life.
    12·1 answer
  • What formula relates mass volume and density?
    11·1 answer
  • The carbon cycle is powered by which two processes?
    12·2 answers
  • Ben and Jerry, arch rivals, decide to have a weight lifting contest during PE. Ready, set, go! Ben and Jerry both lift a 250 kg
    6·2 answers
  • Why is the cathode ray oscilloscope evacuated?
    13·1 answer
  • The medium through which a mechanical wave passes can be a solid, liquid, or gas. Properties of a wave change when it moves from
    14·1 answer
  • What would the person’s mass be on the earth? Part B pls
    7·1 answer
  • A sound with a lot of energy is ____________________ than a sound with less energy.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!