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Hatshy [7]
3 years ago
11

find an equation of the line passing through the point (5 4) and parallel to the line whose equation is y= 2x-6

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0

Answer:

y = 2x - 6

Step-by-step explanation:

Given

Equation: y = 2x - 6

Required

Determine the equation of Point: (5,4)

First, we need to determine the slope of y = 2x - 6

The general form of an equation is y = mx + b

Where m represents the slope;

Hence; m =2

Since the equation and the point are parallel. then they have the same slope (m).

m = 2

Next, is to determine the equation of the point, using the following formula:

m = \frac{y - y_1}{x - x_1}

Where

(x_1,y_1) = (5,4)

So, the equation becomes

2 = \frac{y - 4}{x - 5}

Cross Multiply

y - 4 = 2(x - 5)

Open Bracket

y - 4 = 2x - 10

Make y the subject of formula

y = 2x - 10 + 4

y = 2x - 6

Hence, the equation is y = 2x - 6

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