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zhannawk [14.2K]
3 years ago
10

Factorise t^3+t^2+t+1​

Mathematics
1 answer:
Furkat [3]3 years ago
8 0

Answer:

(t+1)(t^2+1)

Step-by-step explanation:

t^3+t^2+t+1​

(t+1)(t^2+1)

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The diagram shows three forces being applied to a crate on a floor. If the crate is to remain stationary, what amount of force m
frozen [14]

Answer:

800 N

Step-by-step explanation:

I don’t know I just submitted it and that was the answer

7 0
3 years ago
Write the ascending order of 21/50 , 3/50 , 17/25 and 1 , 1/5
avanturin [10]

Answer:

1, 1/5, 3/50, 17/25, 21/50 I think

7 0
3 years ago
Which function is shown in the graph?
muminat

Answer: The correct answer choice is B

Step-by-step explanation:

I graphed each function on the desmos calculator and answer choice B matched the graph.

6 0
3 years ago
A survey of athletes at a high school is conducted, and the following facts are discovered: 13% of the athletes are football pla
nekit [7.7K]

Answer:

The probability that an athlete chosen is either a football player or a basketball player is 56%.

Step-by-step explanation:

Let the athletes which are Football player be 'A'

Let the athletes which are Basket ball player be 'B'

Given:

Football players (A) = 13%

Basketball players (B) = 52%

Both football and basket ball players = 9%

We need to find probability that an athlete chosen is either a football player or a basketball player.

Solution:

The probability that athlete is a football player = P(A)= \frac{13}{100}=0.13

The probability that athlete is a basketball player = P(B)= \frac{52}{100}=0.52

The probability that athlete is both basket ball player and  football player = P(A\cap B) = \frac{9}{100}=0.09

We have to find the probability that an athlete chosen is either a football player or a basketball player P(A\cup B).

Now we know that;

P(A\cup B)= P(A) + P(B) - P(A \cap B)\\\\P(A\cup B) = 0.13+0.52-0.09=0.56\\\\P(A\cup B) = \frac{0.56}{100}=56\%

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.

5 0
3 years ago
The length of two sides of a right triangle are leg:
Goryan [66]

Answer:

11.2m

Step-by-step explanation:

Using Pythagoras,

a²+b²=c²

10²+b²=15²

100+b²=225

b²=225-100

b²=125

b=√125

b=11.2m

8 0
2 years ago
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