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svp [43]
3 years ago
5

Hydrazine is a weak base, kb=3.0x10^-6. find the ph of an aqueous 2.0 m solution of its conjugate acid

Chemistry
1 answer:
zepelin [54]3 years ago
5 0
Answer is: pH of hydrazine conjugate acid is 4.088.
Chemical reaction: N₂H₅⁺ + H₂O ⇄ N₂H₄ + H₃O⁺.
[N₂H₅⁺] = 2.0 M.
[N₂H₄] = [H₃O⁺] = x.
Kb(N₂H₄) = 3.0·10⁻⁶.
Kb·Ka = 1.00·10⁻¹⁴.
Ka(N₂H₅⁺) = 1.00·10⁻¹⁴ ÷ 3.0·10⁻⁶.
Ka = 3.33·10⁻⁹.
Ka = [N₂H₄]·[H₃O⁺] / [N₂H₅⁺].
3.33·10⁻⁹ = x² / 2.0 M.
x = [H₃O⁺] = √3.33·10⁻⁹ · 2.0 M.
[H₃O⁺] =  8.1·10⁻⁵ M.
pH = -log[H₃O⁺].
pH = -log(8.1·10⁻⁵ M).
pH = 4.088.
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<h3>What is photosynthesis?</h3>
  • Photosynthesis is the process by which manufacturers use sunlight, water, and carbon dioxide to produce oxygen and energy in the form of sugar.
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3 0
1 year ago
A 1.93-mol sample of xenon gas is maintained in a 0.805-L container at 306 K. Calculate the pressure of the gas using both the i
Alex

Answer : The pressure of the gas using both the ideal gas law and the van der Waals equation is, 60.2 atm and 44.6 atm respectively.

Explanation :

First we have to calculate the pressure of gas by using ideal gas equation.

PV=nRT

where,

P = Pressure of Xe gas = ?

V = Volume of Xe gas = 0.805 L

n = number of moles Xe = 1.93 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of Xe gas = 306 K

Now put all the given values in above equation, we get:

P\times 0.805L=1.93mole\times (0.0821L.atm/mol.K)\times 306K

P=60.2atm

Now we have to calculate the pressure of gas by using van der Waals equation.

(P+\frac{an^2}{V^2})(V-nb)=nRT

P = Pressure of Xe gas = ?

V = Volume of Xe gas = 0.805 L

n = number of moles Xe = 1.93 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of Xe gas = 306 K

a = pressure constant = 4.19L^2atm/mol^2

b = volume constant = 5.11\times 10^{-2}L/mol

Now put all the given values in above equation, we get:

(P+\frac{(4.19L^2atm/mol^2)\times (1.93mole)^2}{(0.805L)^2})[0.805L-(1.93mole)\times (5.11\times 10^{-2}L/mol)]=1.93mole\times (0.0821L.atm/mol.K)\times 306K

P=44.6atm

Therefore, the pressure of the gas using both the ideal gas law and the van der Waals equation is, 60.2 atm and 44.6 atm respectively.

5 0
3 years ago
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8 0
3 years ago
It is observed that the atoms of hydrogen in gas discharge tube emit radiations whose spectrum shows line characteristics (line
azamat

Answer: the line Spectra of hydrogen lies between the ultra-violet, visible light and infra-red of the electro magnetic spectrum

Explanation:

Electromagnetic radiation spans an wide range of wavelengths and frequencies. This range is called the electromagnetic spectrum. The electromagnetic spectrum is generally divided into seven regions, in order of decreasing wavelength and increasing energy and frequency. The 7 regions includes; radio waves, microwaves, infrared (IR), visible light, ultraviolet (UV), X-rays and gamma rays.

lower-energy radiation, such as radio waves, is expressed as frequency while microwaves, infrared, visible and UV light are usually expressed as wavelength and finally, higher-energy radiation such as X-rays and gamma rays, is expressed in terms of energy per photon.

Therefore, hydrogen lies between the ultra-violet, visible light and infra-red region of the electro magnetic spectrum.

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3 years ago
Which molecule has the greatest difference in electronegativity (DE) between the two different elements? A. CO_2 B. H_2S C. NH_3
Natalka [10]

Answer:

Water has the greatest ΔEN

ΔEN H₂O → 3.4 - 2.1 = 1.3   Option D.

Explanation:

We should find the Electronegativity data in the Periodic table for all the elements:

C : 2.6

O: 3.4

H: 2.1

S: 2.6

N: 3.0

a. ΔEN CO₂ → 3.4 - 2.6 = 0.4

b. ΔEN H₂S → 2.6 - 2.1 = 0.5

c. ΔEN NH₃ → 3 - 2.1= 0.9

d. ΔEN H₂O → 3.4 - 2.1 = 1.3

3 0
4 years ago
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