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3 years ago

How many glucose molecules can be produced per second in a plant

1 answer:

3 0

Since glycolysis of one glucose molecule generates two acetyl CoA molecules, the reactions in the glycolytic pathway and citric acid cycle produce six CO2 molecules, 10 NADH molecules, and two FADH2 molecules per glucose molecule

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1.364mol of H2, 0.682mol of S2 and 0.680mol of H2S were mixed in a 2.00L container at 580°C. At equilibrium the concentration of

kenny6666 [7]

Answer: equilibrium constant = 2.576

3 0

3 years ago

Consider the Gibbs energies at 25 ∘C.

zysi [14]

Answer:

A)ΔGrxn∘=55.7kJ/mol

B)Ksp=1.75×10^−10

C)ΔGrxn∘=70.0kJ/mol

D)Ksp=5.45×10^−13

Explanation:

ΔGrxn∘=ΔGf,products∘−ΔGf,reactants∘

To calculate for the

Ksp

of the dissolution reaction can be claculated

ΔGrxn∘=−RTlnKsp

where R is the proportionality constant equal to 8.3145 J/molK.

ΔGrxn∘=[ΔGf,Ag(aq)+∘+ΔGf,Cl(aq)−∘]−ΔGf,

AgCl(s)⇌Ag(aq)++Cl(aq)−

ΔG∘rxn=[77.1kJ/mol+(−131.2kJ/mol)]−(−109.8kJ/mol)

ΔGrxn∘=55.7kJ/mol

b) Calculate the solubility-product constant of AgCI.

ΔGrxn∘=−RTlnKsp

55.7kJ/mol=−(8.3145×10−3J/molK)(298.15K)InKsp

Ksp=1.75×10^−10

c) Calculate

To calculate ΔG°rxn

for the dissolution of AgBr(s).

ΔGrxn∘=[ΔGf,Ag(aq)+∘+ΔGf,Br(aq)−∘]−ΔGf,

ΔGrxn∘=[77.1kJ/mol+(−104.0kJ/mol)]−(−96.90kj/mol

ΔGrxn∘=70.0kJ/mol

d)To Calculate the solubility-product constant of AgBr.

ΔGrxn∘=−RTlnKsp

70.0kJ/mol=−(8.3145×10−3J/molK)(298.15K)lnKsp

70.0kJ/mol=−(8.3145×10−3J/molK)(298.15K

Ksp=5.45×10^−13

8 0

3 years ago

Okay im clueless and over thinking this question can someone please help me out

Crank

A cookie made from flour, eggs, sugar, butter, and chocolate chips is an example of a heterogeneous mixture.

Also, mixing the sugar flavoring in water, since you're mixing two different states of matter.

6 0

3 years ago

What happens if you choose the wrong solvent while setting up your NMR experiment?

MissTica

Answer:

Please see the answer..hope its works

Explanation:

The NMR spectrometer will acquire data for the wrong chemical shift range and you will potentially have skewed data when opening spinworks-NMR spectrometer examines a specific 12 ppm range based on the expected solvent peak, and if a different solvent is used a different range may be examined

To explain further, If the user declares the wrong solvent, one of two things may happen. Firstly, the spectrometer may not be able to establish a deuterium lock and will report an error and not run the sample. Secondly, the spectrometer may be able to establish a lock despite the fact that the deuterium signal is off resonance. If the lock is established, the field strength will be set to a value appropriate to put the declared solvent signal on-resonance. When a proton NMR spectrum is collected, the chemical shift scale will be incorrect by an amount equal to the proton chemical shift difference between the true solvent and the declared solvent.

7 0

4 years ago

Calcular la normalidad de 1 Kg de sulfuro de aluminio en 5000 ml de solucion.

Troyanec [42]

Calculate the normality of 1 Kg of aluminum sulfide in 5000 ml of solution.

Normality comes out to be 8.11

<h3> Given </h3>

Mass of solute: 1000g
Volume of solution (V): 5000 ml = 5 liters
Equivalent mass of solute (E) = molar mass / n-factor

n-factor for $Al_{2}S_{3}$ is 6 and molar mass is 148g

So, on calculating equivalent mass is equal to 24.66g

FORMULAE of Normality (N) = (Mass of the solute) / (Equivalent mass of the solute (E) × Volume of the solution (V)

N= $\frac{1000}{24.66*5}$

Therefore, normality of 1 kg aluminum sulfide is 8.11

Learn more about normality here brainly.com/question/25507216

#SPJ10

7 0

2 years ago