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4 years ago

In a coffee-cup calorimeter, 50.0ml of 0.100M AgNO3 and50.0ml of 0.100M HCl are mixed to yield the following reaction:

Chemistry

1 answer:

Marina CMI [18]4 years ago

5 0

Answer:

-66.88KJ/mol

Explanation:

It is possible to obtain the heat involved in a reaction using a calorimeter. Formula is:

q = -C×m×ΔT

Where q is heat of reaction, C is specific heat capacity (4.18J/°Cg), m is mass of solution (100.0g) and ΔT is temperature change (23.40°C-22.60°C = 0.80°C)

Replacing:

q = -4.18J/°Cg×100.0g×0.80°C

q = -334.4J

Now, in the reaction:

Ag⁺ + Cl⁻→ AgCl

AgNO₃ as source of Ag⁺ and HCl as source of Cl⁻

Moles that react are:

0.050L× (0.100mol /L) = 0.0050moles

If 0.0050 moles produce -334.4J. Heat of reaction is:

-334.4J / 0.0050moles = -66880J/mol = -66.88KJ/mol

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3 years ago

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3 years ago

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PLEASE HELP! How does one determine how much of a molecule is produced in a reaction?

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3 years ago

175 ml of a 1.6 m solution of kcl is diluted to a new volume of 1.0 l. what is the new concentration of the solution?

zhenek [66]

The new concentration of the KCl solution after mixing 1 L new volume is 0.28 M.

<h3>How do we calculate the concentration?</h3>

Concentration in terms of molarity will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

M₁ = molarity of old KCl solution = 1.6 M

V₁ = volume of old KCl solution = 175 mL = 0.175 L

M₂ = molarity of new KCl solution = ?

V₂ = volume of new KCl solution = 1 L

On putting all these values on the above equation, we get

M₂ = (1.6)(0.175) / (1) = 0.28 M

Hence resultant concentration is 0.28 M.

To know more about molarity, visit the below link:

brainly.com/question/24305514

7 0

2 years ago

Calculate the energy released when 24.8 g Na2O reacts in the following reaction.

gizmo_the_mogwai [7]

Answer:

= 48.077 kcal

Explanation:

The balanced equation is :

$Na_{2}O(s)+2HI(g)\rightarrow 2NaI(s)+H_{2}O(l)$

$\Delta H=-120Kcal$

Since the stoichiometric coefficient of Na2O = 1 hence its heat is

-120 Kcal/mol rather -120 Kcal only.

This means when 1 mole of the Na2O is burned , then 120 kcal of energy is released .

Molar mass of Na2O = 2(mass of Na) + 1(mass of O)

= 2(22.98)+16

=61.97 gram/mol

Molar mass = mass of the substance in grams present in 1 mole of it.

In 1 mole of Na2O , 61.97 gram of it is present.

Hence

61.97 gram of Na2O = -120 Kcal of heat is released

1 gram of Na2O =

$/frac{-120kcal/mol}{61.9gram/mol}$

So,

24.8 gram of Na2O will produce,

$/frac{-120kcal/mol}{61.9gram/mol}/times 24.8$

= -48.077 kcal of heat

You can also proceed through mole concept:

Calculate number of moles in 24.8 gram Na2O

$Moles=\frac{given\ mass}{Molar\ mass}$

Moles of Na2O = 24.08/61.9 = 0.4007 moles

So these many moles will produces:

0.4007 x 120

=-48.07

7 0

3 years ago