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4 years ago

Four identical rectangles form the square. What is the perimeter of the square, if the perimeter of each rectangle is 40 inches?

Mathematics

1 answer:

8090 [49]4 years ago

3 0

Answer:

Step-by-step explanation:

so basically first I wanted to find the width, if you draw a model, it would be easy, so

I make 4 rectangles, one on top of the other for all of them.

so if you turn it clockwise 90 degrees, the rectangles are the same so if you draw them together then they over lap you can see that you can make a x:y for the lengths. If the width of the rectangle is 1 then the length of the rectangle is 4, 1:4 , so now we use the perimeter of 40 so now if the width is w and the length is l then wl is 20 (40/2) si niw 20/(1+4) which is 20/5 which is 4, so now we know that the width of the rectangle is 4 and the length is 4x4 which is 16 so now we can calculate the perimeter of the square, we know that the side length of the square is 16, so all we have to do is 16x4 which is 64.

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Answer:

Step-by-step explanation:

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HELP!!<br> what is the value of w?<br> A.40<br> B.52.5<br> C.75<br> D.100

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The angles w and 80 are inscribed angles in the top left and bottom right corners respectively. They are opposite angles in this inscribed quadrilateral. Because they are opposite angles in the inscribed quadrilateral, they add to 180 degrees.

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Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally

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Answer:

a) 0.1587 (or 15.87%)

b) 0.0478 (or 4.78%)

c) 0.7935 (or 79.35%)

Step-by-step explanation:

Find the following probabilities:

(a) the thickness is less than 3.0 mm

We need to find the area under the Normal curve with a mean of 4.5 mm and a standard deviation of 1.5 mm to the left of 3 mm

<h3>(See picture 1 attached) </h3>

We can do that with the help of a calculator or a spreadsheet.

<em>In Excel use </em>

<em>NORMDIST(3,4.5,1.5,1) </em>

<em>In OpenOffice Calc use </em>

<em>NORMDIST(3;4.5;1.5;1) </em>

and we get the value 0.1587 (or 15.87%)

(b) the thickness is more than 7.0 mm

Now we need the area to the right of 7 (1 - the area to the left of 7)

<h3>(See picture 2 attached) </h3>

<em>In Excel use </em>

<em>1-NORMDIST(7,4.5,1.5,1) </em>

<em>In OpenOffice Calc use </em>

<em>1-NORMDIST(7;4.5;1.5;1) </em>

and we get the value 0.0478 (or 4.78%)

(c) the thickness is between 3.0 mm and 7.0 mm

We are looking for the area between 3 and 7

<h3>(See Picture 3) </h3>

Since the area under the Normal equals 1, we have

Area to the left of 3 + Area between 3 and 7 + Area to the right of 7 = 1

Hence,

0.1587 + Area between 3 and 7 + 0.0478 = 1

and

Area between 3 and 7 = 1 - 0.1587 - 0.0478 = 0.7935 (or 79.35%)

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