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pantera1 [17]
3 years ago
10

There are three executives in an office, ages 56, 57, and 58. If a 57-year-old executive enters the room, the

Mathematics
1 answer:
vova2212 [387]3 years ago
3 0

Answer:

option (c) The mean age will stay the same but the variance will decrease

Step-by-step explanation:

Case I: For 3 executives of ages 56, 57 and 58

Number of executives, n = 3

Mean = \frac{\textup{56 + 57 + 58 }}{\textup{3}}

or

Mean = 57

Variance = \frac{\sum{(Data - Mean)^2}}{\textup{n-1}}

or

Variance = \frac{(56 - 57)^2+(57-57)^2+(58-57)^2}{\textup{3-1}}

or

Variance = \frac{1+0+1}{\textup{2}}

or

Variance = 1

For Case II: For 4 executives of ages 56, 57, 58 and 57

Number of executives, n = 4

Mean = \frac{\textup{56 + 57 + 58 + 57 }}{\textup{4}}

or

Mean = 57

Variance = \frac{\sum{(Data - Mean)^2}}{\textup{n-1}}

or

Variance = \frac{(56 - 57)^2+(57-57)^2+(58-57)^2+(57-57)^2}{\textup{4-1}}

or

Variance = \frac{1+0+1+0}{\textup{3}}

or

Variance = 0.67

Hence,

Mean will remain the same and the variance will decrease

Hence,

The correct answer is option (c) The mean age will stay the same but the variance will decrease

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Find the average value of the function f(t)=(t-2)^2 on [0,6]
pentagon [3]

Answer:

2

Step-by-step explanation:

The "average value of function f(x) on interval [a, b] is given by:

                      f(b) - f(a)

ave. value = ---------------

                         b - a

Here f(t)=(t-2)^2.

Thus, f(b) = (b - 2)^2.  For b = 6, we get:

          f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16

For a = 0, we get:

           f(0) = (0 - 2)^2 = 4

Plugging these results into the ave. value function shown above, we get:

                      16 - 4

ave. value = ------------ = 12/6 = 2

                         6 - 0

The average value of the function f(t)=(t-2)^2 on [0,6] is 2.


4 0
3 years ago
The question is in the file.
Tasya [4]
Can you ask me the question because your file is not showing up for me,
4 0
3 years ago
Read 2 more answers
What is the sum _71/6 +35/6 in the simplest terms ? Show your work
adoni [48]

Answer:

The answer in simplest term is 35.33333334.

Step-by-step explanation:

First, we need to divide 71 and 6.

71/6 = 23.66666667.

Now we need to divide 35 and 6.

35/6 = 11.66666667.

Now we need to add the two quotients.

23.66666667 + 11.66666667 = 35.33333334.

And that is the final answer.

I hope this helps!

7 0
3 years ago
Describe and correct the error below.
Sergeeva-Olga [200]
Cos ( 390)
- 4 cot (-45)
Csc (60)
Hope this helps
6 0
2 years ago
If the area of a baseball diamond (shape of a square) is 8100 ft squared, how would you find the distance from 1st base to 3rd b
Readme [11.4K]

Answer:

  • Exact distance = 90\sqrt{2} feet
  • Approximate distance = 127.2792 feet.

===========================================================

Explanation:

The area of the square is 8100 square feet, abbreviated ft^2.

Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.

If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).

Use the pythagorean theorem to find the hypotenuse.

a^2 + b^2 = c^2\\\\c = \sqrt{a^2+b^2}\\\\c = \sqrt{90^2+90^2}\\\\c = \sqrt{2*90^2}\\\\c = \sqrt{2}*\sqrt{90^2}\\\\c = \sqrt{2}*90\\\\c = 90\sqrt{2} \ \text{ ... exact distance}\\\\c \approx 127.2792 \ \text{ ... approximate distance}\\\\

The distance from 1st to 3rd base is roughly 127.2792 feet.

5 0
2 years ago
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