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3 years ago

5

What is 4/14 simplified

2 answers:

Serggg [28]3 years ago

8 0

2/7 is the simplification form

natima [27]3 years ago

3 0

4\14 in simplest form is 2\7

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Agata [3.3K]

Answer:

41.15

Step-by-step explanation:

41.15

7 0

3 years ago

sally is 1 year older than3 times the age of joe. chris is 5 years younger than 6 times the age of joe. if sally and chris are t

Lina20 [59]

6x - 5 = 3x + 1
-3x -3x
————————
3x - 5 = 1
+ 5 + 5
————————
3x = 6
—— —
3 3

x = 2
Joe is 2 years old.

~~~~~~~~~~~~~~~~
Check

6(2) - 5 = 3(2) + 1
12 - 5 = 6 + 1
✔️
7 = 7

5 0

4 years ago

How do you solve 8(y-7) = -16

Kaylis [27]

8 (y - 7) = - 16

Divide by 8 on both sides

y - 7 = - 2

Add 7 to both sides

y = 5

3 0

3 years ago

Read 2 more answers

Hey.. I’m really stuck on this page of homework, can anyone help?

eduard

Answer:

Easy!

Step-by-step explanation:

All you have to do is.. Percentage = (number you want to find the percentage for ÷ total) × 100. Move the decimal point two places to the right to convert from a decimal to a percentage, and two places to the left to convert from a percentage to a decimal.

Hope this helps :)

3 0

3 years ago

Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

LiRa [457]

we know that

A polynomial in the form $a^{3}-b^{3}$ is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

<u>case A)</u> $9w^{33} -y^{12}$

we know that

$9=3^{2}$ ------> <u>the term is not a perfect cube</u>

$w^{33}=(w^{11})^{3}$ ------> the term is a perfect cube

$y^{12}=(y^{4})^{3}$ ------> the term is a perfect cube

therefore

The expression $9w^{33} -y^{12}$ is not a difference of cubes because the term $9$ is not a perfect cube

<u>case B)</u> $18p^{15} -q^{21}$

we know that

$18=2*3^{2}$ ------> <u>the term is not a perfect cube</u>

$p^{15}=(p^{5})^{3}$ ------> the term is a perfect cube

$q^{21}=(q^{7})^{3}$ ------> the term is a perfect cube

therefore

The expression $18p^{15} -q^{21}$ is not a difference of cubes because the term $18$ is not a perfect cube

<u>case C)</u> $36a^{22} -b^{16}$

we know that

$36=2^{2}*3^{2}$ ------> <u>the term is not a perfect cube</u>

$a^{22}$ ------> <u>the term is not a perfect cube</u>

$b^{16}$ ------> <u>the term is not a perfect cube</u>

therefore

The expression $36a^{22} -b^{16}$ is not a difference of cubes because all terms are not perfect cubes

<u>case D)</u> $64c^{15} -a^{26}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$a^{26}$ ------> <u>the term is not a perfect cube</u>

therefore

The expression $64c^{15} -a^{26}$ is not a difference of cubes because the term $a^{26}$ is not a perfect cube

I'm adding a new case so I can better explain the problem

<u>case E)</u> $64c^{15} -d^{27}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$d^{27}=(d^{9})^{3}$ ------> the term is a perfect cube

Substitute

$64c^{15} -d^{27}=((2^{2})(c^{5}))^{3}-(d^{9})^{3}$

therefore

The expression $64c^{15} -d^{27}$ is a difference of cubes because all terms are perfect cubes

5 0

3 years ago

Read 2 more answers