Given that f(x) = ax – 5 and f(4) = 15, then the value of a is 5
The given function is:
f(x) = ax - 5
If f(4) = 15, then x = 4
Substitute x = 4 into f(x) = ax - 5
f(4) = a(4) - 5
15 = 4a - 5
Solve for a by adding 5 to both sides
15 + 5 = 4a - 5 + 5
20 = 4a
Divide both sides by 4
4a/4 = 20/4
a = 5
Given that f(x) = ax – 5 and f(4) = 15, then the value of a is 5
Learn more on linear functions here: brainly.com/question/15602982
Answer:
( a+b) (a-b)
x^2 - 50
Step-by-step explanation:
The formula for difference of squares is
a^2 - b^2 = ( a+b) (a-b)
121x^2 -144 = (11x)^2 - 12^2 so this is the difference of squares
x^2 - 16y^2 = (x)^2 - (4y)^2 so this is the difference of squares
9x^2 -64 = (3x)^2-8^2 so this is the difference of squares
x^2 - 50 = (x)^2 - 2*(5)^2 this is not the difference of squares
Kenneth wrote per page is 4
Answer:
(2,3)
Step-by-step explanation:
