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IrinaK [193]
3 years ago
12

Help please!!!!!! and explanation if possible

Mathematics
1 answer:
loris [4]3 years ago
6 0
The correct answer is 3



the triangle sides are equal. so :
4x - 1 = 2x + 5 \\ 4x - 2x = 1 + 5 \\ 2x = 6 \\ x =  \frac{6}{2}  = 3



good luck
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3 years ago
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30 POINTS PLEASE ANSWER ASAP. The Diagram shows the front wooden wall of the warehouse in the shape of a trapezoid with a rectan
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HELP PLEASE FIND X AND SHOW YOUR WORK
PtichkaEL [24]

Answer:

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Step-by-step explanation:

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So to find "x", we need to figure out what the full number is.

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Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when X = 59.5. So

Z = \frac{X - \mu}{\sigma}

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Z = 3.1 has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0
3 years ago
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