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nikdorinn [45]
4 years ago
12

What is the factors of 12

Mathematics
1 answer:
adoni [48]4 years ago
7 0
Factors of 12 include- 1, 2, 3, 4, 6,
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The time college students spend on the internet follows a Normal distribution. At Johnson University, the mean time is 5 hrs wit
netineya [11]

Answer:

The probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5

Step-by-step explanation:

We are given that . At Johnson University, the mean time is 5 hrs with a standard deviation of 1.2 hrs.

Mean = \mu = 5 hours

Standard deviation = \sigma = 1.2 hours

We are supposed to find the probability that the average time 100 random students on campus will spend more than 5 hours on the internet i.e. P(X>5)

Z=\frac{x-\mu}{\sigma}

Z=\frac{5-5}{1.2}

Z=0

P(X>5)=1-P(X<5)=1-P(Z<0)=1-0.5=0.5

Hence the probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5

7 0
3 years ago
Please help soon!! I will give brainliest to the first correct answer!
Sladkaya [172]

Answer:

1(left) goes with 1

2(left)  goes with 3

3(left) goes with 2

4(left) goes with 4

Step-by-step explanation:

2(5+6) = 22


3(5+3) = 24


2(4+5) = 18


2(3+2) = 10  

10 + 12 = 22  

8+ 10 = 18


15 + 9 = 24


6 + 4 = 10

1(left) goes with 1

2(left)  goes with 3

3(left) goes with 2

4(left) goes with 4

5 0
3 years ago
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For each of 3 years, the table above gives the number of different routes a runner ran, the number of runs she ran, and the tota
Ksju [112]
No way i can answer this impossible 
6 0
3 years ago
Answer these please!!!!
Anuta_ua [19.1K]
#13
Letter D
We don't know if 5 = 6 or
6 = 8

#14
You need slope and y- intercept. It is a negative slope because the line is going down from left to right. Count rise over run.

M = - 4/6 = -2/3
If the line continued to the y axis it would cross at 10.
y = -2/3x + 10
7 0
3 years ago
(2x^{2}-7x-8)+(5x^{2}-2x+9) <br> whats the sum
pshichka [43]

Answer:

the answerrrrrrrrrrr is 7x^2-9x+1

3 0
3 years ago
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