$\text{Standard Score, z} =\dfrac{X-\mu}{\sigma} $ where:\\\\Mean Pulse rate, \mu =67.3$ beats per minute\\Standard Deviation, \sigma = 10.3$ beats per minute.\\$

For a male student who has a measured pulse rate of 52 beats per minute.

Raw Score, X =52 beats per minute.

Therefore:

$\text{Standard Score, z} =\dfrac{52-67.3}{10.3}\\z=-1.49$

Since the usual pulse rates are within 2 standard deviations of the mean, a z-score of -1.49 tells us that the selected student's pulse rate is within the usual pulse rates.

8 0

4 years ago

I need help please fast .................

erastova [34]

Answer:

I have no idea what sohcahtoa is but:

tan 50.1° = x/5

1.196 = x/5

multiply both sides of the equation by 5:

x = 5.98

3 0

3 years ago

Samuel starts off with 125 to spend on shirts and ties samuel buys 3 shirts for 24.50 each ties cost 14.50 how many toes can sam

Luden [163]

Samuel could buy 3 ties.

3 0

3 years ago

The equation of the graphed line is x+2y=5. What is the x-intercept of the graph?

Monica [59]

Answer:

5 is the answer. hhhjjh y fl jj g gshwhwjqjajajw

5 0

3 years ago