The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB
Enzymes, or digestive juices, are secreted by the pancreas into the small intestine. There, it continues breaking down food that has left the stomach. The pancreas also produces the hormone insulin and secretes it into the bloodstream, where it regulates the body's glucose or sugar level.
Answer:
Organism.
Explanation:
The cell is the smallest form of life. Cells work together to form tissues, tissues work together to form organs, and organs work together to create an organ system, and organ systems work together to create organisms. I believe "organism" includes all of these other levels.
1.
Anaphase. In <span>Anaphase the sister chromatids separate from each other to the opposite sides of the cells.
2. </span>
Chromosomes would not separate into two nuclei. <span>Mitosis is a process cell division, where one cell divides into two identical cells.
</span>
3.
Metaphase I. <span>Meiosis prophase I is the phase in which chromosomal crossing over occurs. The phase after prophase I is metaphase I.
4. </span>
Its body cells would have 36 chromosomes, and its gametes would have 18 chromosomes. <span>In the gametes, there are half of the number of chromosomes present in the body cell.
5. </span><span>
A species has to adjust rapidly to a changing environment. To adjust to the environment, crossing over is necessary, and it does not occur in mitosis, but meiosis.
6.
50 percent. Parents: Yy x yy
Offspring: Yy Yy yy yy
50 % is Yy and 50% is yy.
7. </span><span>
One parent had white eyes and the other was heterozygous for eye color. The ratio in the offspring is 50-50. The only possibility is the following:
Parents: Rr x rr
Offspring Rr Rr Rr Rr
8. </span><span>
Their fur will be a mixture of red and white hairs. The offspring will be heterozygous. They will have alleles for both red and white hairs and both will be expressed.
</span>
9. Not enough information.
10. <span>
Both of the parents' genotype must have been Pp. The genotype of the white plant is pp since it is recessive:
Parents: Pp x Pp
Offspring: PP Pp Pp pp
One of the four is white.</span>
The answer is “C”. Natural selection is about ones traits being better than another’s which allow it to survive in the wilds longer.
