Answer:
Equivalent resistance in series = 6 + 3 = 9 ohms
Current = V/R (ohm's law)
Current = 9/9 = 1 A
P.D. across 6 ohms = IR (ohm's law)
= 1A × 6Ω = 6V
Answer:
Explanation:
For image formation in objective lens
object distance u = 14 +1 = 15 mm
focal length f = 14 mm .
image distance v = ?
lens formula
Putting the values
v = 210 mm .
B )
magnification = v / u
= 210 / 15
= 14
size of image = 14 x 1.1 mm
= 15.4 mm
= 15 mm approx
C )
For final image to be at infinity , image produced by objective lens must fall at the focal point of eye piece . so objective lens's distance from the image formed by objective must be equal to focal length of eye piece that is 21 mm .
21 mm is the answer .
D )
overall magnification =
D = 25 cm , f_e = focal length of eye piece
= 14 x 250 / 21
= 166.67
= 170 ( in two significant figures )
Answer:
Charge, q = 900 C
Explanation:
It is given that,
Current flowing through the circuit, I = 6 A
Time for the flow of current, t = 2.5 minutes = 150 seconds
We have to find the charge delivered to this circuit. The total charge per unit time is called the current flowing through the circuit. It q is the charge flowing, then :
q = I × t
q = 6 A × 150 s
q = 900 coulomb
So, 900 coulomb of charge is delivered to this circuit.
Answer:
S = 2 π R
R (mean) = 92.9E6 miles
S = 2 * 3.14 * 92.9E6 miles = 5.84E8 miles