Democritus was the one who did not have experimental evidence to support his theory of the atom.
Answer: Option 4
<u>Explanation:
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The discovery of atoms were first stated by Democritus but due to the absence of any experimental proof, his statement was not noted as significant at that time.
After this, Dalton made the specific assumptions formulating some postulates for the atomic theory with proof. Then the cathode rays tube experiments performed by Thomson lead to the formation of plum pudding models of atom.
This is followed by Rutherford’s gold foil experiment discovering the presence of nucleus inside the atoms. So, Democritus first stated but due to absence of experimental evidences, his theory of atoms were not supported at that time.
Answer:
Stress = F / A force per unit area
A = 3.00 cm^2 = 3 E-4 m^2
F = 2.4E8 N/m^2 * 3E-4 m^2 = 7.2E4 N max force applied
F/3 = 2.4E4 N if force not to exceed limit (= f)
f = M a
a = 2.4 E4 N / 1.2 E3 kg = 20 m / s^2 about 2 g
Answer:
A 2 N force pulling and a 10 N force pulling left while a 12N force pulls right.
Answer:
864 KN
Explanation:
(Absolute pressure) = (Atmospheric pressure) + (Gauge Pressure)
Atmospheric pressure = 95 KPa = 95000 Pa
Gauge Pressure = ρgh
ρ = density of the fluid = 1000 kg/m³
g = acceleration due to gravity = 9.8 m/s²
h = depth below the fluid level that the object is at = 5 m
Gauge Pressure = 1000 × 9.8 × 5 = 49000 Pa
Absolute pressure = 95000 + 49000 = 144000 Pa.
Pressure = (Hydrostatic force)/(Area perpendicular to the force)
Hydrostatic force = (Pressure) × (Area perpendicular to the force)
Area perpendicular to the force = 2 × 3 = 6 m²
Hydrostatic force on the top of the plate = 144000 × 6 = 864000 N = 864 KN
Hope this Helps!!!
Answer:
m1/m2 = 0.51
Explanation:
First to all, let's gather the data. We know that both rods, have the same length. Now, the expression to use here is the following:
V = √F/u
This is the equation that describes the relation between speed of a pulse and a force exerted on it.
the value of "u" is:
u = m/L
Where m is the mass of the rod, and L the length.
Now, for the rod 1:
V1 = √F/u1 (1)
rod 2:
V2 = √F/u2 (2)
Now, let's express V1 in function of V2, because we know that V1 is 1.4 times the speed of rod 2, so, V1 = 1.4V2. Replacing in the equation (1) we have:
1.4V2 = √F/u1 (3)
Replacing (2) in (3):
1.4(√F/u2) = √F/u1 (4)
Now, let's solve the equation 4:
[1.4(√F/u2)]² = F/u1
1.96(F/u2) =F/u1
1.96F = F*u2/u1
1.96 = u2/u1 (5)
Now, replacing the expression of u into (5) we have the following:
1.96 = m2/L / m1/L
1.96 = m2/m1 (6)
But we need m1/m2 so:
1.96m1 = m2
m1/m2 = 1/1.96
m1/m2 = 0.51
