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inessss [21]
3 years ago
15

a man is standing near the edge of a cliff 85 meters high. he throws a stone upward vertically with an intial velocity of 10 m/s

. the stone clears the cliff edge on the way down and falls all the way to the ground. what is the maximum height of the stone above the ground
Physics
1 answer:
alex41 [277]3 years ago
5 0

Answer:

h = 90.10 m

Explanation:

Given that,

A man is standing near the edge of a cliff 85 meters high, h₀ = 85 m

The initial speed of the stone, u = 10 m/s

The path followed by the projectile is given by :

h(t)=-4.9t^2+10t+85 ....(1)

For maximum height,

Put dh/dt = 0

So,

\dfrac{dh}{dt}=-9.8t+10=0\\\\t=\dfrac{10}{9.8}\\\\=1.02\ s

Put the value of t in equation (1).

h(t)=-4.9(1.02)^2+10(1.02)+85\\\\=90.10\ m

So, the maximum height of the stone is equal to 90.10 m.

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A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver's velocity re
natka813 [3]

Answer: Workdone293.02KJ

Explanation: The equation to use to calculate Workdone = Change in KE + Change in PE

Assuming velocity is constant,KE becomes 0

Workdone= Change in PE=mg

W=92×9.8×325=293.02KJ

5 0
3 years ago
two horses on opposite sides of a narrow stream are pulling a barge along the stream. Each horse pulls with a force of 720N. The
Setler [38]
Each horse's force forms a right angle triangle with the barge and subtends an angle of 60/2 = 30°. The resultant in the direction of the barge's motion is:
Fx = Fcos(∅)
We can multiply this by 2 to find the resultant of both horses.
Fx = 2Fcos(∅)
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3 0
3 years ago
The intensity I of light from a light​ bulb, measured in watts per square meter ​(w/m squared​), varies inversely as the square
DerKrebs [107]

Answer:

157.5W/m^2

Explanation:

We are given that

I=70w/m^2

When d=3 m

We have to find the intensity when the distance from the light bulb is 2 m away.

According to question

Intensity,I\propto\frac{1}{d^2}

I=\frac{kd^2}

Where k=Proportionality constant.

Substitute the values

70=\frac{k}{3^2}

k=70\times 3^2=630

Intensity when d=2 m

I=\frac{630}{2^2}=157.5W/m^2

6 0
3 years ago
Please help meeeee!!! ​
prohojiy [21]

Answer:

1. Test tube

2. tongs

3.

4.  FUNNEL

5.  

6.

7. Flask

8. Beaker

9. Bunsen burner

10. Erlenmeyer Flask

11.  Molar and pestle

12. Wire gauze

13.  Graduated cylinder

14. Test tube rack

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8 0
3 years ago
You should have observed that there are some frequencies where the output is stronger than the input. Discuss how that is even p
nydimaria [60]

Answer:

w = √ 1 / CL

This does not violate energy conservation because the voltage of the power source is equal to the voltage drop in the resistence

Explanation:

This problem refers to electrical circuits, the circuits where this phenomenon occurs are series RLC circuits, where the resistor, the capacitor and the inductance are placed in series.

In these circuits the impedance is

             X = √ (R² +  (X_{C} -X_{L})² )

where Xc and XL is the capacitive and inductive impedance, respectively

            X_{C} = 1 / wC

           X_{L} = wL

From this expression we can see that for the resonance frequency

           X_{C} = X_{L}

the impedance of the circuit is minimal, therefore the current and voltage are maximum and an increase in signal intensity is observed.

This does not violate energy conservation because the voltage of the power source is equal to the voltage drop in the resistence

               V = IR

Since the contribution of the two other components is canceled, this occurs for

                X_{C} = X_{L}

                1 / wC = w L

                w = √ 1 / CL

6 0
3 years ago
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