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AveGali [126]
3 years ago
11

A baseball player slides into third base with an initial speed of 4.0 m/s. If the coefficient of

Physics
2 answers:
Scrat [10]3 years ago
6 0
<span>The frictional force is given by F = μmg

where μ is the coeficient of friction.

Work done by frictional force = Fd = μmgd

Kinetic energy "lost" = 1/2 mv² 

Since we know that W = ΔK,

so,  Fd = μmgd = 1/2 mv²

The m's cancel μgd = v² / 2

d = v² / 2μg

d =  4² / 2(0.46)(9.81)

d =  16 / 2(0.46)(9.81)

d =  1.77

Player slides 1.77 m .

</span>
musickatia [10]3 years ago
3 0
The frictional force is given by F = μmg 

<span>where μ is the coeficient of friction. </span>

<span>Work done by frictional force = Fd = μmgd </span>

<span>Kinetic energy "lost" = 1/2 mv² </span>


<span>Fd = μmgd = 1/2 mv² </span>

<span>The m's cancel μgd = v² / 2 </span>



<span>d = v² / 2μg </span>

<span>d = 8² / 2(0.41)(9.8) </span>

<span>d = 32 / (0.41)(9.8) </span>

<span>d = 7.96 </span>

<span>Player slides 8 m . </span>



<span>Note. In your other example μ = 0.46 and v = 4 m/s </span>



<span>d = v² / 2μg </span>




<span>= 4² / 2(0.46)(9.8) </span>

<span>= 8 / (0.46)(9.8) </span>

<span>= 1.77 or 1.8 m.
</span>
Hope i Helped :D
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2 years ago
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When water freezes, its volume increases by 9.05% (that is, equation). What force per unit area is water capable of exerting on
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Answer:

1.991 × 10^(8) N/m²

Explanation:

We are told that its volume increases by 9.05%.

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3 years ago
Lexy throws a dart with an initial velocity of 25 m/s at an angle of 60° relative to the ground. what is the approximate vertica
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A coin is placed on a large disk which rotates uniformly at a rate of 1 rot/s. The coefficient of friction between the coin and
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Answer:

r = 0.02 m

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speed = 1 rps = 1x 60 = 60 rpm

coefficient of friction (μ) = 0.1

acceleration due to gravity (g) = 9.8 m/s^{2}

maximum distance without falling off (r) = ?

to get how far from the center of the disk the coin can be placed without having to slip off we equate the formula for the centrifugal force with the frictional force on the turntable force

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