Answer:
(4, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 2x - 7
y = -x + 5
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 2x - 7 = -x + 5
- [Addition Property of Equality] Isolate <em>x</em> terms: 3x - 7 = 5
- [Addition Property of Equality] Isolate <em>x</em> term: 3x = 12
- [Division Property of Equality] Isolate <em>x</em>: x = 4
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = -x + 5
- Substitute in <em>x</em>: y = -4 + 5
- Add: y = 1
Answer:
Get a line of which you want to know the slope. Make sure that the line is straight.
Pick any two coordinates that the line goes through. Coordinates are the x and y points written as ( x, y ).
Pick which point's coordinates are dominant in your equation. ...
Set up the equation using the y-coordinates on top and the x-coordinates on bottom.
(-3,2)(1,2)...notice that the y values are the same.....when the y values are the same u have a horizontal line with a 0 slope.
IF the x values would have been the same (instead of the y values), then u would have had a vertical line with an undefined slope.
Well to solve this firstly we should calculate her average speed while she was going to work. Which comes out to be 45 miles per hour.
Now if her average speed while going home is half as fast as while coming to work was, the answer would be 22.5 miles per hour. So the average speed for the total journey would be the average for these two values. As the distance was same for both the journeys we can simply do 45 + 22.5 / 2 = 33.75 mph.
32,667 that will be in numbers
