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3 years ago

Find the mean of this set of numbers.

1 answer:

7 0

You would add them all together and then divide the answer by how many numbers are there in this case there are 6 so you would all all 6 numbers then divide by 6

So all the numbers added together is 12 so then divide 12 and 6

the mean would be 6

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How to solve polynomials?

liberstina [14]

Factoring:

FOIL (first, outer, inner, last) method

(a+b)(c+d) = 0

ac+ad+bc+bd = 0

Zeros:

(x+a)(x+b) = 0

x+a = 0, x= 0-a

x+b = 0, x= 0-b

4 0

3 years ago

Identify the inequalities A, B, and C for which the given ordered pair is a solution: (0,0)<br>

professor190 [17]

Answer:

Options (A) and (C)

Step-by-step explanation:

A). The given inequality is,

x + y ≤ 2

Solution area of the inequality is the shaded area below the line.

Since (0, 0) lies in the shaded region, ordered pair will be a solution of this inequality.

B). For the inequality y ≤ $\frac{3}{2}x-1$

Since, (0, 0) doesn't lie in the shaded region of this inequality, ordered pair will not be a solution of the inequality.

C). y > $-\frac{1}{3}x-2$

In this graph (0, 0) lies in the shaded region of the inequality therefore, it will be a solution of the given inequality.

Therefore, Options (A) and (C) are the correct options.

5 0

3 years ago

Shakira has 6 whole dollars, 3 hundredths of a dollar, and 7 tenths of a dollar. How much money does she have? What coins/bills

algol13

Answer:

$6.73

Step-by-step explanation:

Since it says "answer in coins" she could have 24 quarters, 7 dimes, and 3 pennies.

I believe this correct but im not exactly sure

I hope this helps :)

7 0

3 years ago

Read 2 more answers

Suppose c>d. explain why the following inequalities are true:

Aneli [31]

Answer: Optional

Step-by-step explanation:

Since c is greater than d, 2c would be greater than 2d, because when it’s like this 2c

It sometimes means multiply.

7 0

3 years ago

(5/6)^4x=(36/25)^9-x, please help solve for x, and the 9-x is all superscript

stiks02 [169]

$\frac{36}{25}=\frac{6^2}{5^2}=\left(\frac{6}{5}\right)^2=\left(\frac{5}{6}\right)^{-2}\\\\therefore:\\\\\left(\frac{5}{6}\right)^{4x}=\left[\left(\frac{5}{6}\right)^{-2}\right]^{9-x}\\\\\left(\frac{5}{6}\right)^{4x}=\left(\frac{5}{6}\right)^{-2(9-x)}\iff4x=-2(9-x)\\\\4x=-2\cdot9-2\cdot(-x)\\\\4x=-18+2x\ \ \ \ \ |subtract\ 2x\ from\ both\ sides\\\\2x=-18\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{x=-9}$

$Use:\\a^{-n}=\left(\frac{1}{a}\right)^n\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\\left(\frac{a}{b} \right)^n=\frac{a^n}{b^n}$

6 0

3 years ago

Read 2 more answers