It is true. here is how........
4-0 is rounding down
5-9 is rounding up
when rounding to the tenths place you look at the hundredths place to find the answer.
For AD:
AD=root((c-0)^2 + (d-0)^2)=root((c)^2 + (d)^2)
For BC:
BC=root(((b+c) - b)^2+(d-0)^2)=root((c)^2+(d)^2)
For AB:
AB=root((b-0)^2 + (0-0)^2)=root((b)^2 + (0)^2)=root((b)^2)
For CD:
CD=root((c-(b+c))^2 + (d-d)^2)
CD=root((b)^2 + (0)^2)
CD=root((b)^2)
Answer:
z = 0
Step-by-step explanation:
3 (z + 7) = 21
3z + 21 = 21
3z = 0
z = 0
For question 4: you have to do (y2 - y1) divided by (x2 - x1) to get the rise over run...
5-2
——. = 3/4
11 - 7
For question 5: input the values of x,y and the gradient into the equation of a line.....
y = mx+ c
-8 = 3(-2) + c
-8 = -6 + c
-2 = c
therefore:
y = 3x - 2
Hope this helps! Any questions let me know :)
Answer:
The equation of Grant's path is y = 4 - x over 2 ⇒ 2nd answer
Step-by-step explanation:
The form of the linear equation is y = m x + b, where
- m is the slope of the line
- b is the y-intercept (value y at x = 0)
The formula of the slope of a line is
∵ Grant's path is a line from point A to point B
∴ The equation of AB represents Grant's path
Lets find the slope of AB using the formula of the slope above
∵ A = (8 , 0)
∵ B = (-4 , 6)
∴ = 8 and = -4
∴ = 0 and = 6
∵
∴
Substitute the value of m in the form of the equation
∵ y = m x + b
∴ y = x + b
∵ b is the value of y at x = 0
∵ y = 4 at x = 0 ⇒ from the figure
∴ b = 4
∴ y = x + 4
We can write x as
∴ y = + 4
- Switch the two terms of the right hand side
∴ y = 4 -
The equation of Grant's path is y = 4 -