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ANTONII [103]
4 years ago
12

Consider a binomial experiment with n = 8 trials and p = 0.20.

Mathematics
1 answer:
kumpel [21]4 years ago
6 0
A. np is the mean=8×0.20=1.60; variance=np(1-p)=1.60×0.80=1.28. Standard deviation=√variance=1.13 approx.
b. The coefficients for n=8 are: 1, 8, 28, 56, 70, 56, 28, 8, 1.
The first 4 of these are involved in getting 5 or more successes. Let q=1-p. p=0.20 and q=0.80.
So we have p⁸+8p⁷q+28p⁶q²+56p⁵q³=0.0104... This is a very low probability, so it would be unusual to obtain 5 or more successes.
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3 years ago
How to find the discriminant of
Sonbull [250]

the discriminant   b^2 - 4ac when the equation is in the form of ax^2 +bx+c=0

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we need to get in it the standard form

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