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Charra [1.4K]
3 years ago
5

What would the wavelength of a photon be if its energy is 4.79x10-19 J?

Chemistry
1 answer:
Softa [21]3 years ago
8 0

Answer:

λ = 4.2 × 10⁻⁷ m

Explanation:

Given data:

Energy of photon = 4.79 × 10 ⁻¹⁹ J

Wavelength of photon = ?

Solution:

E = h.c / λ

λ = h. c/ E

λ = 6.63× 10⁻³⁴m² kg/s × 3×10⁸ m/s / 4.79 × 10 ⁻¹⁹ Kg m²/s²

λ = 19.89 × 10⁻²⁶ kg. m³ /s² / 4.79 × 10 ⁻¹⁹ Kg m²/s²

λ = 4.2 × 10⁻⁷ m

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The correct answer is a.) C. Oxidation occurs when an element loses electrons and increases its oxidation state. In the chemical equation, Carbon in CH4 has an oxidation state of 4- while Carbon in CO2 has an oxidation of 4+.
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2.50g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 12
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Answer:

                      Molecular Formula  =  C₁₀H₈

Explanation:

Step 1: <u>Calculating Moles for each Element:</u>

C  =  Mass of CO₂ × (1 mol of CO₂÷ M.Mass of CO₂) × (1 mol of C ÷ 1 mol of CO₂)

C  =  8.60 g × (1 mol of CO₂÷ 44.011 g.mol⁻¹) × (1 mol of C ÷ 1 mol of CO₂)

C =  0.1954 mol

H  =  Mass of H₂O × (1 mol of H₂O ÷ M.Mass of H₂O) × (2 mol of H ÷ 1 mol of H₂O)

H  = 1.41 g × (1 mol of H₂O ÷ 18.106 g.mol⁻¹) × (2 mol of H ÷ 1 mol of H₂O)

H =  0.1557 mol

Step 2: <u>Calculate the Smallest whole number ratio as,</u>

                                 C                                                        H

                              0.1954                                               0.1557

                      0.1954/0.1557                                  0.1557/0.1557

                               1.25                                                       1

Multiply ratio by 4,

                                 5                                                         4

Result:

          Empirical Formula of Propane is C₅H₄

Step 3: <u>Calculate Molecular Formula:</u>

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  128.0 g.mol⁻¹

Empirical Formula Weight  =  5 (C) + 4 (H) =  64 g.mol⁻¹

So,

                     n  =  128.0 g.mol⁻¹ ÷ 64 g.mol⁻¹

                     n  =  2

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 2 × C₅H₄

                    Molecular Formula  =  C₁₀H₈

4 0
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0.1144 kg=\frac{35.274}{1}\times 0.1144=4.04ounce


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